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[link] shows a different random sampling of 20 cell phone models. Use this data to calculate a 93% confidence interval for the true mean SAR for cell phones certified for use in the United States. As previously, assume that the population standard deviation is σ = 0.337.
Phone Model | SAR | Phone Model | SAR |
---|---|---|---|
Blackberry Pearl 8120 | 1.48 | Nokia E71x | 1.53 |
HTC Evo Design 4G | 0.8 | Nokia N75 | 0.68 |
HTC Freestyle | 1.15 | Nokia N79 | 1.4 |
LG Ally | 1.36 | Sagem Puma | 1.24 |
LG Fathom | 0.77 | Samsung Fascinate | 0.57 |
LG Optimus Vu | 0.462 | Samsung Infuse 4G | 0.2 |
Motorola Cliq XT | 1.36 | Samsung Nexus S | 0.51 |
Motorola Droid Pro | 1.39 | Samsung Replenish | 0.3 |
Motorola Droid Razr M | 1.3 | Sony W518a Walkman | 0.73 |
Nokia 7705 Twist | 0.7 | ZTE C79 | 0.869 |
Z 0.035 = 1.812
– EBM = 0.940 – 0.1365 = 0.8035
+ EBM = 0.940 + 0.1365 = 1.0765
We estimate with 93% confidence that the true SAR mean for the population of cell phones in the United States is between 0.8035 and 1.0765 watts per kilogram.
Notice the difference in the confidence intervals calculated in [link] and the following Try It exercise. These intervals are different for several reasons: they were calculated from different samples, the samples were different sizes, and the intervals were calculated for different levels of confidence. Even though the intervals are different, they do not yield conflicting information. The effects of these kinds of changes are the subject of the next section in this chapter.
Suppose we change the original problem in [link] by using a 95% confidence level. Find a 95% confidence interval for the true (population) mean statistics exam score.
To find the confidence interval, you need the sample mean, , and the EBM .
CL = 0.95 so α = 1 – CL = 1 – 0.95 = 0.05
The area to the right of z 0.025 is 0.025 and the area to the left of z 0.025 is 1 – 0.025 = 0.975.
when using invnorm(0.975,0,1) on the TI-83, 83+, or 84+ calculators. (This can also be found using appropriate commands on other calculators, using a computer, or using a probability table for the standard normal distribution.)
EBM = (1.96) = 0.98
– EBM = 68 – 0.98 = 67.02
+ EBM = 68 + 0.98 = 68.98
Notice that the EBM is larger for a 95% confidence level in the original problem.
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