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By the end of this section, you will be able to:
  • Determine the angular frequency of oscillation for a resistor, inductor, capacitor ( R L C ) series circuit
  • Relate the R L C circuit to a damped spring oscillation

When the switch is closed in the RLC circuit    of [link] (a), the capacitor begins to discharge and electromagnetic energy is dissipated by the resistor at a rate i 2 R . With U given by [link] , we have

d U d t = q C d q d t + L i d i d t = i 2 R

where i and q are time-dependent functions. This reduces to

L d 2 q d t 2 + R d q d t + 1 C q = 0 .
Figure a is a circuit with a capacitor, an inductor and a resistor in series with each other. They are also in series with a switch, which is open. Figure b shows the graph of charge versus time. The charge is at maximum value, q0, at t=0. The curve is similar to a sine wave that reduces in amplitude till it becomes zero.
(a) An RLC circuit. Electromagnetic oscillations begin when the switch is closed. The capacitor is fully charged initially. (b) Damped oscillations of the capacitor charge are shown in this curve of charge versus time, or q versus t . The capacitor contains a charge q 0 before the switch is closed.

This equation is analogous to

m d 2 x d t 2 + b d x d t + k x = 0 ,

which is the equation of motion for a damped mass-spring system (you first encountered this equation in Oscillations ). As we saw in that chapter, it can be shown that the solution to this differential equation takes three forms, depending on whether the angular frequency of the undamped spring is greater than, equal to, or less than b /2 m . Therefore, the result can be underdamped ( k / m > b / 2 m ) , critically damped ( k / m = b / 2 m ) , or overdamped ( k / m < b / 2 m ) . By analogy, the solution q ( t ) to the RLC differential equation has the same feature. Here we look only at the case of under-damping. By replacing m by L , b by R , k by 1/ C , and x by q in [link] , and assuming 1 / L C > R / 2 L , we obtain

q ( t ) = q 0 e R t / 2 L cos ( ω t + ϕ )

where the angular frequency of the oscillations is given by

ω = 1 L C ( R 2 L ) 2

This underdamped solution is shown in [link] (b). Notice that the amplitude of the oscillations decreases as energy is dissipated in the resistor. [link] can be confirmed experimentally by measuring the voltage across the capacitor as a function of time. This voltage, multiplied by the capacitance of the capacitor, then gives q ( t ).

Try an interactive circuit construction kit that allows you to graph current and voltage as a function of time. You can add inductors and capacitors to work with any combination of R , L , and C circuits with both dc and ac sources.

Try out a circuit-based java applet website that has many problems with both dc and ac sources that will help you practice circuit problems.

Check Your Understanding In an RLC circuit, L = 5.0 mH , C = 6.0 μ F , and R = 200 Ω . (a) Is the circuit underdamped, critically damped, or overdamped? (b) If the circuit starts oscillating with a charge of 3.0 × 10 −3 C on the capacitor, how much energy has been dissipated in the resistor by the time the oscillations cease?

a. overdamped; b. 0.75 J

Got questions? Get instant answers now!

Summary

  • The underdamped solution for the capacitor charge in an RLC circuit is
    q ( t ) = q 0 e R t / 2 L cos ( ω t + ϕ ) .
  • The angular frequency given in the underdamped solution for the RLC circuit is
    ω = 1 L C ( R 2 L ) 2 .

Key equations

Mutual inductance by flux M = N 2 Φ 21 I 1 = N 1 Φ 12 I 2
Mutual inductance in circuits ε 1 = M d I 2 d t
Self-inductance in terms of magnetic flux N Φ m = L I
Self-inductance in terms of emf ε = L d I d t
Self-inductance of a solenoid L solenoid = μ 0 N 2 A l
Self-inductance of a toroid L toroid = μ 0 N 2 h 2 π ln R 2 R 1 .
Energy stored in an inductor U = 1 2 L I 2
Current as a function of time for a RL circuit I ( t ) = ε R ( 1 e t / τ L )
Time constant for a RL circuit τ L = L / R
Charge oscillation in LC circuits q ( t ) = q 0 cos ( ω t + ϕ )
Angular frequency in LC circuits ω = 1 L C
Current oscillations in LC circuits i ( t ) = ω q 0 sin ( ω t + ϕ )
Charge as a function of time in RLC circuit q ( t ) = q 0 e R t / 2 L cos ( ω t + ϕ )
Angular frequency in RLC circuit ω = 1 L C ( R 2 L ) 2

Questions & Answers

what does the ideal gas law states
Joy Reply
Three charges q_{1}=+3\mu C, q_{2}=+6\mu C and q_{3}=+8\mu C are located at (2,0)m (0,0)m and (0,3) coordinates respectively. Find the magnitude and direction acted upon q_{2} by the two other charges.Draw the correct graphical illustration of the problem above showing the direction of all forces.
Kate Reply
To solve this problem, we need to first find the net force acting on charge q_{2}. The magnitude of the force exerted by q_{1} on q_{2} is given by F=\frac{kq_{1}q_{2}}{r^{2}} where k is the Coulomb constant, q_{1} and q_{2} are the charges of the particles, and r is the distance between them.
Muhammed
What is the direction and net electric force on q_{1}= 5µC located at (0,4)r due to charges q_{2}=7mu located at (0,0)m and q_{3}=3\mu C located at (4,0)m?
Kate Reply
what is the change in momentum of a body?
Eunice Reply
what is a capacitor?
Raymond Reply
Capacitor is a separation of opposite charges using an insulator of very small dimension between them. Capacitor is used for allowing an AC (alternating current) to pass while a DC (direct current) is blocked.
Gautam
A motor travelling at 72km/m on sighting a stop sign applying the breaks such that under constant deaccelerate in the meters of 50 metres what is the magnitude of the accelerate
Maria Reply
please solve
Sharon
8m/s²
Aishat
What is Thermodynamics
Muordit
velocity can be 72 km/h in question. 72 km/h=20 m/s, v^2=2.a.x , 20^2=2.a.50, a=4 m/s^2.
Mehmet
A boat travels due east at a speed of 40meter per seconds across a river flowing due south at 30meter per seconds. what is the resultant speed of the boat
Saheed Reply
50 m/s due south east
Someone
which has a higher temperature, 1cup of boiling water or 1teapot of boiling water which can transfer more heat 1cup of boiling water or 1 teapot of boiling water explain your . answer
Ramon Reply
I believe temperature being an intensive property does not change for any amount of boiling water whereas heat being an extensive property changes with amount/size of the system.
Someone
Scratch that
Someone
temperature for any amount of water to boil at ntp is 100⁰C (it is a state function and and intensive property) and it depends both will give same amount of heat because the surface available for heat transfer is greater in case of the kettle as well as the heat stored in it but if you talk.....
Someone
about the amount of heat stored in the system then in that case since the mass of water in the kettle is greater so more energy is required to raise the temperature b/c more molecules of water are present in the kettle
Someone
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ALIYU
field is a region of space under the influence of some physical properties
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WISDOM
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a=v/t. a=f/m a
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Esrael
Two bodies attract each other electrically. Do they both have to be charged? Answer the same question if the bodies repel one another.
JALLAH Reply
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Dlovan
Are you really asking if two bodies have to be charged to be influenced by Coulombs Law?
Robert
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Raymond
Practice Key Terms 1

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Source:  OpenStax, University physics volume 2. OpenStax CNX. Oct 06, 2016 Download for free at http://cnx.org/content/col12074/1.3
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