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The empirical formula of a chemical compound is a simple expression of the relative number of each type of atom in that compound. In contrast, the molecular formula of a chemical compound gives the actual number of atoms of each element found in a molecule of that compound.
The empirical formula of a chemical compound gives the relative number of each type of atom in that compound.
The molecular formula of a chemical compound gives the exact number of atoms of each element in one molecule of that compound.
The compound ethanoic acid for example, has the molecular formula CH COOH or simply C H O . In one molecule of this acid, there are two carbon atoms, four hydrogen atoms and two oxygen atoms. The ratio of atoms in the compound is 2:4:2, which can be simplified to 1:2:1. Therefore, the empirical formula for this compound is CH O. The empirical formula contains the smallest whole number ratio of the elements that make up a compound.
Knowing either the empirical or molecular formula of a compound, can help to determine its composition in more detail. The opposite is also true. Knowing the composition of a substance can help you to determine its formula. There are three different types of composition problems that you might come across:
Calculate the percentage that each element contributes to the overall mass of sulfuric acid ( ).
Hydrogen = 1.008 2 = 2.016 u
Sulfur = 32.07 u
Oxygen = 4 16 = 64 u
Use the calculations in the previous step to calculate the molecular mass of sulfuric acid.
Use the equation:
Percentage by mass = atomic mass / molecular mass of H SO 100%
Hydrogen
Sulfur
Oxygen
(You should check at the end that these percentages add up to 100%!)
In other words, in one molecule of sulfuric acid, hydrogen makes up 2.06% of the mass of the compound, sulfur makes up 32.69% and oxygen makes up 65.25%.
A compound contains 52.2% carbon (C), 13.0% hydrogen (H) and 34.8% oxygen (O). Determine its empirical formula.
Carbon = 52.2 g, hydrogen = 13.0 g and oxygen = 34.8 g
Therefore,
In this case, the smallest number of moles is 2.18. Therefore...
Carbon
Hydrogen
Oxygen
Therefore the empirical formula of this substance is: . Do you recognise this compound?
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