10.2 Adding and subtracting vectors  (Page 20/4)

Its easy to understand the problem if we first draw a quick sketch. The rough sketch should include all of the information given in the problem. All of the magnitudes of the displacements are shown and a compass has been included as a reference direction. In a rough sketch one is interested in the approximate shape of the vector diagram.

The choice of scale depends on the actual question – you should choose a scale such that your vector diagram fits the page.

It is clear from the rough sketch that choosing a scale where 1 cm represents 2 km (scale: 1 cm = 2 km) would be a good choice in this problem. The diagram will then take up a good fraction of an A4 page. We now start the accurate construction.

Starting at the harbour H we draw the first vector 3 cm long in the direction north.

Since the ship is now at port A we draw the second vector 6 cm long starting from point A in the direction east.

Since the ship is now at port B we draw the third vector 2,25 cm long starting from this point in the direction south-west. A protractor is required to measure the angle of 45 ${}^{\circ }$ .

As a final step we draw the resultant displacement from the starting point (the harbour H) to the end point (port C). We use aruler to measure the length of this arrow and a protractor to determine its direction.

We now use the scale to convert the length of the resultant in the scale diagram to the actual displacement in the problem. Since we have chosen a scale of 1 cm = 2 km in this problem the resultant has a magnitude of 9,2 km. The direction can be specified in terms of the angle measured either as 072,3 ${}^{\circ }$ east of north or on a bearing of 072,3 ${}^{\circ }$ .

The resultant displacement of the ship is 9,2 km on a bearing of 072,3 ${}^{\circ }$ .