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The static friction has dual role here. If “T” and “R” denotes translation and rotation respectively, then :

W fT = F r = - f S x

and

W fR = τ θ = f S R θ

where “θ” is total angle covered during the motion. For rolling motion,

θ = x R

Putting the expression of angle in equation – 8,

W fR = f S R x x R = f S x

The work done by friction in translation and rotation are equal, but opposite in sign. The net work by friction is zero.

Thus, total work done by the external forces is :

W = M g x sin θ

We find that work by friction in rolling is zero. It is so because it does negative work in translation and equal positive work in rotation. There may be situations in which friction does positive work in translation and negative work in rotation. For example, if a body is initially given angular velocity greater than linear velocity required by equation of rolling, then the friction does the positive work in translation (accelerates translation) and negative work in rotation (decelerates rotation). Here also, net work by friction is zero in rolling.

Mechanical energy of rolling body

Mechanical energy comprises of potential and kinetic energy of the rolling body. These two forms of energy is described, in reference to rolling, as here :

Potential energy

We must have observed the conspicuous absence of reference to the potential energy in rotation. The reason is simple. The rotating body does not change its center of mass over a period of time in pure rotation. There is no change in the body – Earth configuration due to rotation. This is a valid approximation for a relatively small body such that its mass distribution with respect to Earth remains same.

If a body is rolling along a straight line on a horizontal surface, then there is no change in potential energy as COM of the rolling body remains at same vertical height from the ground. In the case of rolling along an incline, the COM of the rolling body changes elevation and as such there is change in the gravitational potential energy of the body – Earth system (Note that potential energy is always referred to a system – not to a single body like kinetic energy. When we assign potential energy to a body, the reference to Earth or other force field is implicit). It must be borne in mind that potential energy changes in rolling is on account of translation only.

Change in potential energy

The potential energy changes as vertical elevation of the body changes.

Δ U = M g h

where “h” is the change in vertical elevation.

Kinetic energy

Unlike potential energy, kinetic energy arises from both translation and rotation. The kinetic energy of rolling body is a positive sum of translational and rotational kinetic energies. The total kinetic energy of a rolling body is given by :

K = K T + K R = 1 2 x M V C 2 + 1 2 x I ω 2

Looking at the expressions of translational and rotational kinetic energy, we find that we can convert the expression either in terms of linear or angular velocity, using equation of rolling,

v C = ω R

Total kinetic energy in terms of linear velocity,

K = ( I + M R 2 ) x V C 2 2 R 2

Total kinetic energy in terms of angular velocity,

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
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cm
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A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
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Can you compute that for me. Ty
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what is inorganic
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Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
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A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
Krampah Reply
2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
Sahid Reply
you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
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Maurice Reply
what are the types of wave
Maurice
answer
Magreth
progressive wave
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Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
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Source:  OpenStax, Physics for k-12. OpenStax CNX. Sep 07, 2009 Download for free at http://cnx.org/content/col10322/1.175
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