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All other code for the fish counting project

Code for the fish classifier

% This function is one of the top level files that call all the tests and % figure out which fish their results indicate. It also adds noise to the image% to start with. function [fishtype]= fishcounterback(file) fish = imread(file);fishimage1 = im2double(fish); % Add noise to the picturenoise = randn(size(fishimage1)); noiselevel = .00;fishimagenoise = fishimage1 + noiselevel.*noise; fishimagenoisevals = and(fishimagenoise<1, fishimagenoise>0); fishimage = fishimagenoise.*fishimagenoisevals;fishmod = 0; if sum(sum(rgb2gray(fishimage)))>100% If the length to width ratio is less than 2.85 and greater than 2,% its a salmon, and if its greater than 3.5, the fish is a trout. [length,width,lwratio]= fishedge(fishimage); if and(lwratio<= 2.85, lwratio>2) fishmod = fishmod + 1;elseif lwratio >=3.5 fishmod = fishmod - 1;end% Check to see how much intensity there is in each of the color spectrums for i = 1:3fishnorm(:,:,i) = fishimage(:,:,i)./norm((fishimage(:,:,i)));intensitymatrix(:,:,i) = reshape(fishimage(:,:,i), 1, prod(size(fishimage(:,:,1)))); intensity(:,:,i) = mean(intensitymatrix(:,:,i));endrgintens = intensity(:,:,1)-intensity(:,:,2); rbintens = intensity(:,:,1)-intensity(:,:,3);% If the red is greater than one ofthe other spectrums by at least .4, then% it is a trout, if they are within .1 of each other, it is a trout. Otherwise % it is an unknown item.if rgintens >.04 fishmod = fishmod + .5;elseif rgintens<.01 fishmod = fishmod - .5;endif rbintens >.04 fishmod = fishmod + .5;elseif rbintens<.01 fishmod = fishmod - .5;end% Check the features of the fish. [body,head,tail]= featureanalyzer(fishimage);% If the body is red and the head is green, blue, or both, then its a trout. % If the body is all three colors and either the head or the tail or both% are the same color and included in the body, then it is a trout. if and(body == 'r ', or(head == 'g ', or(head == 'gb ', head == 'b ')))fishmod = fishmod + 1.5; endif and(body == 'rgb', and(head == 'cbd', tail == 'cbd')) fishmod = fishmod - 1.5;elseif and(body == 'rgb', or(head == 'cbd', tail == 'cbd')) fishmod = fishmod - 1;end%Count the fins on the fish. If it is zero, then its probably trash, % otherwise, keep the modifier in its present state.numfins = findet(fishimage);if and(numfins == 0, abs(fishmod)<=2) fishmod = 0;endelse fishmod = 0;end % If most of the tests think the fish is a salmon, call it a salmon% If most of the tests think the fish is a trout, call it a trout % If the tests all don't know, or if they disagree, call it unknownif fishmod >0 fishtype = 'salmon ';elseif fishmod<0 fishtype = 'trout ';else fishtype = 'unknown';end

Code for the mass fish counter

% This is the top file for the whole system. It takes in a matrix of filenames and % a matrix of what type of fish each of the files is. It then runs the classification% program on one fish at a time and then computes the accuracy of the outputs. function [fishmatrix,statsmat,correct,wrong]= massfishcounter(filematrix,typematrix); for fishnum = 1:size(filematrix,1)fishnum% Classify the current fish fishmatrix(fishnum,:) = fishcounter(filematrix(fishnum,:));end salmoncount = 0;troutcount = 0; undetermined = 0;correct = 0; wrong = 0;salcor = 0; troutcor = 0;undetcor = 0; salwrong = 0troutwrong = 0; undetwrong = 0;salmonpercent = 0; troutpercent = 0;undetpercent = 0; % Check all of the output types to the input matrix of which type each% fish should be and see how accurate the results were. for z = 1:size(fishmatrix,1)switch fishmatrix(z,:) case 'salmon 'salmoncount = salmoncount + 1; if fishmatrix(z,:)==typematrix(z,:);salcor = salcor + 1; elsesalwrong = salwrong + 1; endcase 'trout ' troutcount = troutcount + 1;if fishmatrix(z,:)==typematrix(z,:); troutcor = troutcor + 1;else troutwrong = troutwrong + 1;end case 'unknown'undetermined = undetermined + 1; if fishmatrix(z,:)==typematrix(z,:);undetcor = undetcor + 1; elseundetwrong = undetwrong + 1; endend endsalmonpercent = salcor./(salcor+salwrong); troutpercent = troutcor./(troutcor+troutwrong);undetpercent = undetcor./(undetcor+undetwrong);correct = salcor + troutcor + undetcor; wrong = salwrong + troutwrong + undetwrong;statsmat = [salcor salwrong salmonpercent; troutcor troutwrong troutpercent; undetcor undetwrong undetpercent];
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Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
Aislinn Reply
cm
tijani
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John Reply
what is physics
Siyaka Reply
A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
Jude Reply
Can you compute that for me. Ty
Jude
what is the dimension formula of energy?
David Reply
what is viscosity?
David
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emma Reply
what is chemistry
Youesf Reply
what is inorganic
emma
Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
Adjei
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Adjanou
chemistry could also be understood like the sexual attraction/repulsion of the male and female elements. the reaction varies depending on the energy differences of each given gender. + masculine -female.
Pedro
A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
Krampah Reply
2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
Sahid Reply
you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
Ryan
what's motion
Maurice Reply
what are the types of wave
Maurice
answer
Magreth
progressive wave
Magreth
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Muhammad Reply
fine, how about you?
Mohammed
hi
Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
yasuo Reply
Who can show me the full solution in this problem?
Reofrir Reply
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Source:  OpenStax, Ece 301 projects fall 2003. OpenStax CNX. Jan 22, 2004 Download for free at http://cnx.org/content/col10223/1.5
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