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Why don’t we notice Heisenberg’s uncertainty principle in everyday life? The answer is that Planck’s constant is very small. Thus the lower limit in the uncertainty of measuring the position and momentum of large objects is negligible. We can detect sunlight reflected from Jupiter and follow the planet in its orbit around the Sun. The reflected sunlight alters the momentum of Jupiter and creates an uncertainty in its momentum, but this is totally negligible compared with Jupiter’s huge momentum. The correspondence principle tells us that the predictions of quantum mechanics become indistinguishable from classical physics for large objects, which is the case here.

Heisenberg uncertainty for energy and time

There is another form of Heisenberg’s uncertainty principle     for simultaneous measurements of energy and time . In equation form,

Δ E Δ t h , size 12{ΔE Δt>= { {h} over {4π} } } {}

where Δ E size 12{ΔE} {} is the uncertainty in energy    and Δ t size 12{Δt} {} is the uncertainty in time    . This means that within a time interval Δ t size 12{Δt} {} , it is not possible to measure energy precisely—there will be an uncertainty Δ E size 12{ΔE} {} in the measurement. In order to measure energy more precisely (to make Δ E size 12{ΔE} {} smaller), we must increase Δ t size 12{Δt} {} . This time interval may be the amount of time we take to make the measurement, or it could be the amount of time a particular state exists, as in the next [link] .

Heisenberg uncertainty principle for energy and time for an atom

An atom in an excited state temporarily stores energy. If the lifetime of this excited state is measured to be 1.0×10 10 s size 12{"10" rSup { size 8{ - "10"} } `s} {} , what is the minimum uncertainty in the energy of the state in eV?

Strategy

The minimum uncertainty in energy Δ E size 12{ΔE} {} is found by using the equals sign in Δ E Δ t h /4 π size 12{ΔE Δt>= h"/4"π} {} and corresponds to a reasonable choice for the uncertainty in time. The largest the uncertainty in time can be is the full lifetime of the excited state, or Δ t = 1.0×10 10 s size 12{Δt="10" rSup { size 8{ - "10"} } `s} {} .

Solution

Solving the uncertainty principle for Δ E size 12{ΔE} {} and substituting known values gives

Δ E = h 4πΔt = 6 . 63 × 10 –34 J s ( 1.0×10 –10 s ) = 5 . 3 × 10 –25 J. size 12{ΔE= { {h} over {4πΔt} } = { {6 "." "63 " times " 10" rSup { size 8{"–34"} } " J " cdot " s"} over {4π \( "10" rSup { size 8{"–10"} } " s" \) } } =" 5" "." "3 " times " 10" rSup { size 8{"–25"} } " J" "." } {}

Now converting to eV yields

Δ E = (5.3 × 10 –25 J) ( 1 eV 1 . 6 × 10 –19 J ) = 3 . 3 × 10 –6 eV . size 12{ΔE =" 5" "." "3 " times " 10" rSup { size 8{"–25"} } " J " cdot { {"1 eV"} over {1 "." "6 " times " 10" rSup { size 8{"–19"} } " J"} } =" 3" "." "3 " times " 10" rSup { size 8{"–6"} } " eV" "." } {}

Discussion

The lifetime of 10 10 s size 12{"10" rSup { size 8{ - "10"} } `s} {} is typical of excited states in atoms—on human time scales, they quickly emit their stored energy. An uncertainty in energy of only a few millionths of an eV results. This uncertainty is small compared with typical excitation energies in atoms, which are on the order of 1 eV. So here the uncertainty principle limits the accuracy with which we can measure the lifetime and energy of such states, but not very significantly.

The uncertainty principle for energy and time can be of great significance if the lifetime of a system is very short. Then Δ t size 12{Δt} {} is very small, and Δ E size 12{ΔE} {} is consequently very large. Some nuclei and exotic particles have extremely short lifetimes (as small as 10 25 s size 12{"10" rSup { size 8{ - "25"} } `s} {} ), causing uncertainties in energy as great as many GeV ( 10 9 eV size 12{"10" rSup { size 8{9} } `"eV"} {} ). Stored energy appears as increased rest mass, and so this means that there is significant uncertainty in the rest mass of short-lived particles. When measured repeatedly, a spread of masses or decay energies are obtained. The spread is Δ E size 12{ΔE} {} . You might ask whether this uncertainty in energy could be avoided by not measuring the lifetime. The answer is no. Nature knows the lifetime, and so its brevity affects the energy of the particle. This is so well established experimentally that the uncertainty in decay energy is used to calculate the lifetime of short-lived states. Some nuclei and particles are so short-lived that it is difficult to measure their lifetime. But if their decay energy can be measured, its spread is Δ E size 12{ΔE} {} , and this is used in the uncertainty principle ( Δ E Δ t h /4 π ) to calculate the lifetime Δ t size 12{Δt} {} .

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
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Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
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Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
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"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
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Source:  OpenStax, Basic physics for medical imaging. OpenStax CNX. Feb 17, 2014 Download for free at http://legacy.cnx.org/content/col11630/1.1
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