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In many situations, we seek to check consistency of the observations with some preconceived model. Alternative modelsare usually difficult to describe parametrically since inconsistency may be beyond our modeling capabilities. We needa test that accepts consistency of observations with a model or rejects the model without pronouncing a more favoredalternative. Assuming we know (or presume to know) the probability distribution of the observations under 0 , the models are

  • 0 : r p r 0 r
  • 1 : r p r 0 r
Null hypothesis testing seeks to determine if the observations are consistent with this description. Thebest procedure for consistency testing amounts to determining whether the observations lie in a highly probable region asdefined by the null probability distribution. However, no one region defines a probability that is less than unity. We mustrestrict the size of the region so that it best represents those observations maximally consistent with the model whilesatisfying a performance criterion. Letting P F be a false-alarm probability established by us, we define the decision region 0 to satisfy 0 r 0 r 0 p r 0 r 1 P F and 0 r 0 Usually, this region is located about the mean, but may not be symmetrically centered if the probability density isskewed. Our null hypothesis test for model consistency becomes r 0 "say observations are consistent" r 0 "say observations are not consistent"

Consider the problem of determining whether the sequence r l , l 1 L , is white and Gaussian with zero mean and unit variance. Stated this way, the alternative modelis not provided: is this model correct or not? We could estimate theprobability density function of the observations and test the estimate for consistency. Here we take the null-hypothesistesting approach of converting this problem into a one-dimensional one by considering the statistic r l l r l 2 , which has a L 2 . Because this probability distribution is unimodal, the decision region can be safely assumed to be an interval r r .

This one-dimensional result for the consistency test may extend to the multi-dimensional casein the obvious way.
In this case, we can find an analytic solution to the problem of determining the decision region.Letting R r r denote the width of the interval, we seek the solution of the constrained optimization problem r R subject to P r r R P r r 1 P F We convert the constrained problem into an unconstrained one using Lagrange multipliers. r R P r r R P r r 1 P F Evaluation of the derivative of this quantity with respect to r yields the result p r r R p r r : to minimize the interval's width, the probability density function's values at the interval's endpoints must beequal. Finding these endpoints to satisfy the constraints amounts to searching the probability distribution at suchpoints for increasing values of R until the required probability is contained within. For L 100 and P F 0.05 , the optimal decision region for the L 2 distribution is 78.82 128.5 . demonstrates ten testing trials for observations that fit the model and forobservations that don't.
Ten trials of testing a 100-element sequence for consistency with a white, Gaussian model - r l 0 1 - for three situations. In the first (shown by the circles), the observations do conform to the model.In the second (boxes), the observations are zero-mean Gaussian but with variance two. Finally, the thirdexample (crosses) has white observations with a density closely resembling the Gaussian: a hyperbolic secantdensity having zero mean and unit variance. The sum of squared observations for each example are shown with theoptimal 100 2 interval displayed. Note how dramatically the test statistic departs from the decision interval whenparameters disagree.

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Source:  OpenStax, Statistical signal processing. OpenStax CNX. Dec 05, 2011 Download for free at http://cnx.org/content/col11382/1.1
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