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In hypothesis testing , as in all other areas of statistical inference, there are two major schools of thought on designing good tests:Bayesian and frequentist (or classical). Consider the simple binary hypothesis testing problem 0 : x f 0 x 1 : x f 1 x In the Bayesian setup, the prior probability i i of each hypothesis occurring is assumed known. This approach to hypothesis testing is represented by the minimum Bayes risk criterion and the minimum probability of error criterion .

In some applications, however, it may not be reasonable to assign an a priori probability to a hypothesis. For example, what is the a priori probability of a supernova occurring in any particular region of the sky? What is the prior probability of being attacked by aballistic missile? In such cases we need a decision rule that does not depend on making assumptions about the a priori probability of each hypothesis. Here the Neyman-Pearson criterion offers an alternative to the Bayesianframework.

The Neyman-Pearson criterion is stated in terms of certain probabilities associated with a particular hypothesis test. The relevant quantities are summarized in . Depending on the setting, different terminology is used.

Statistics Signal Processing
Probability Name Notation Name Notation
P 0 declare 1 size false-alarm probability P F
P 1 declare 1 power detection probability P D

Here P i declare j dentoes the probability that we declare hypothesis j to be in effect when i is actually in effect. The probabilities P 0 declare 0 and P 1 declare 0 (sometimes called the miss probability), are equal to 1 P F and 1 P D , respectively. Thus, P F and P D represent the two degrees of freedom in a binary hypothesis test. Note that P F and P D do not involve a priori probabilities of the hypotheses.

These two probabilities are related to each other through the decision regions . If R 1 is the decision region for 1 , we have P F x R 1 f 0 x P D x R 1 f 1 x The densities f i x are nonnegative, so as R 1 shrinks, both probabilities tend to zero. As R 1 expands, both tend to one. The ideal case, where P D 1 and P F 0 , cannot occur unless the distributions do not overlap ( i.e. , x f 0 x f 1 x 0 ). Therefore, in order to increase P D , we must also increase P F . This represents the fundamental tradeoff in hypothesis testing and detection theory.

Consider the simple binary hypothesis test of a scalar measurement x : 0 : x 0 1 1 : x 1 1 Suppose we use a threshold test x 0 1 where is a free parameter. Then the false alarm and detection probabilities are P F t 1 2 t 2 2 Q P D t 1 2 t 1 2 2 Q 1 where Q denotes the Q-function . These quantities are depicted in .

False alarm and detection values for a certain threshold.
Since the Q -function is monotonicaly decreasing, it is evident that both P D and P F decay to zero as increases. There is also an explicit relationship P D Q Q P F 1 A common means of displaying this relationship is with a receiver operating characteristic (ROC) curve, which is nothing more than a plot of P D versus P F ( ).
ROC curve for this example.

The neyman-pearson lemma: a first look

The Neyman-Pearson criterion says that we should construct our decision rule to have maximum probability ofdetection while not allowing the probability of false alarm to exceed a certain value . In other words, the optimal detector according to theNeyman-Pearson criterion is the solution to the following constrainted optimization problem:

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
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2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
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can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
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Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
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"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
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A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
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Source:  OpenStax, Signal and information processing for sonar. OpenStax CNX. Dec 04, 2007 Download for free at http://cnx.org/content/col10422/1.5
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