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Motivation for inverse kinematics in proteins

One important application of inverse kinematics is in determining missing portions of protein structure. We traditionally depend on experimentaltechniques to provide us with the picture of an average structure for a protein. X-ray crystallography for example, relies on crystallizing proteinsand reporting the structure of the protein crystal within a certain resolution. One of the inherent problems with X-ray crystallography is thatmobile protein regions such as loops cause disorder in the crystal and as a consequence, coordinates for the atoms of these mobile regions cannot bereported. Often, in the PDB, crystallographically determined proteins are partially resolved, i.e. a portion of the structure may be missing due to itsintrinsic mobility. Even when experimental techniques such as NMR and cryo-EM can report an average picture of the fully resolved protein, the averagestructure reported is not indicative of the different conformations mobile regions can assume inside our cells at room temperature.

The specific problem of completing a partially resolved protein structure by finding conformations for its missing loop is known as the fragmentcompletion or the loop closure problem. Note that the loop closure problem is actually an inverse kinematics problem. Using sequence information alone, i.e.knowing the aminoacid sequence of the missing loop, one can generate starting loop conformations. The loop closure problem requires these loopconformations to be geometrically constrained by attaching them to the portion of the protein structure that is experimentally determined.Note that, as the picture below indicates, one can generate many loop conformations in space through forward kinematics. One end of the loop can beattached to its counterpart in the protein through translation alone. The other end however, needs to be attached without breaking bonds or stretchingbond angles. One way to do this is through inverse kinematics; that is, knowing the goal position in space for the end of the loop, can we solve forthe dihedral DOFs of the loop conformation? This question can be answered by Inverse Kinematics techniques.

One "sticky" end of the loop can be attached to its stationary counterpart in the protein through translation. The other endneeds to move towards its goal location by solving an Inverse Kinematics problem.

Inverse kinematics for a polypeptide chain

Cyclic coordinate descent (ccd)

In this assignment you will complete a loop portion in the 1COA structure of the CI2 protein. X-ray crystallography completely resolves the 1COAstructure. However, even though a long loop region from residue 34 to residue 46 is present in the native conformation of 1COA, an interestingexercise is to pretend this loop region cannot be determined. Using an inverse kinematics approach, you will sample many potential loops that canall complete the 1COA structure and compare them to the native conformation obtained through X-ray crystallography. An important questionto answer is whether your loop closure algorithm can recover/predict the conformational state of this loop region in CI2; that is, how differentare your loops from the one in the native conformation of CI2? You will implement a simple inverse kinematics technique, Cyclic Coordinate Descent(CCD) as presented in . For simplicity, you will work with the native backbone of CI2, whose respective native coordinates you can also obtain from the backbone_native.crd file.

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
Aislinn Reply
cm
tijani
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John Reply
what is physics
Siyaka Reply
A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
Jude Reply
Can you compute that for me. Ty
Jude
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David Reply
what is viscosity?
David
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emma Reply
what is chemistry
Youesf Reply
what is inorganic
emma
Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
Adjei
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Adjanou
chemistry could also be understood like the sexual attraction/repulsion of the male and female elements. the reaction varies depending on the energy differences of each given gender. + masculine -female.
Pedro
A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
Krampah Reply
2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
Sahid Reply
you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
Ryan
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Maurice Reply
what are the types of wave
Maurice
answer
Magreth
progressive wave
Magreth
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Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
yasuo Reply
Who can show me the full solution in this problem?
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Source:  OpenStax, Geometric methods in structural computational biology. OpenStax CNX. Jun 11, 2007 Download for free at http://cnx.org/content/col10344/1.6
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