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When this happens, the result is a partially resolved protein structure, with fragments of the protein chain,such as mobile loops, missing. The only information available for the missing fragment is its amino acid sequence and where its twoendpoints need to be spatially located in order to connect with the known, resolved, part of the protein structure. Given the spatialconstraints on the endpoints of the missing fragment, one needs to find values to the dihedral angles of the fragment in order toobtain configurations of the fragment consistent with the constraints. This problem is known as the Loop Closure problem inthe structural biology community. It is easy to note that even though this problem is cast in the context of finding atomicpositions of a missing fragment such as a mobile loop, it is nothing new but a statement of the Inverse Kinematics problem for proteins.

Solving the Inverse Kinematics problem in the context of a missing fragment in proteins is not limited tofinding mobile loops. More generally, through the Inverse Kinematics problem, one can search for alternative configurations of anyfragment of a protein polypeptide chain (even fragments containing secondary structural elements) that satisfy the spatial constraintson their endpoints. Very recently, a third application has emerged, where alternative configurations of consecutive fragments that covera polypeptide chain are generated to obtain an ensemble of alternative protein structures.

Solving inverse kinematics

In applying inverse kinematics algorithms to proteins, we are taking advantage of a striking similarity between organic molecules androbotic manipulators (robot arms) in terms of how they move. As robot manipulators have joints, proteins have atoms. As robotmanipulators have links that connect their joints, proteins have bonds that connect their atoms. The similarity between proteins androbots makes it possible for us to apply to proteins a large existing literature of solutions to the Inverse Kinematics problem,developed in the context of robot manipulators (robotic arms).

Before we proceed with some simple inverse kinematics examples, note that inverse kinematics isthe inverse of the forward kinematics problem. Therefore, an immediate attempt to solve the inverse kinematics problem would beby inverting forward kinematics equations.

Let's illustrate how to solve the inverse kinematics problem for robot manipulators on a simple example. Thefigure below shows a simple planar robot with two arms. The underlying degrees of freedom of this robot are the two anglesdictating the rotation of the arms. These are labeled in the figure below as θ1 and θ2. The inverse kinematics question in this case wouldbe: What are the values for the degrees of freedom so that the endeffector of this robot (the tip of the last arm) lies at position (x,y) in the two-dimensional Cartesian space? One straightforward approach to solving the problem is to try to write down theforward kinematics equations that relate (x,y) to the two rotational degrees of freedom (see Forward Kinematics for details on how to do so), then try to solve these equations. The solutions will give you an answer to the inverse kinematics problem for thisrobot.

Simple example

Steer end-effector to (x, y) target position.

Non-unique solutions

Two solutions depicted for this IK problem.
Illustration of solving the Inverse Kinematics problem for a simple planar robot with two arms. Figure is adapted from MathWorks .

Given an (x, y) target position for the end-effector of a robot with only two degrees of freedom θ1 and θ2, what are the solutions for θ1 and θ2?

You can compare your answer with the derivation steps below.

Simple example solved

Finding solutions to θ1 and θ2 from the forward kinematics equations of the 2-arm planar robot.
You can see that there can be 0, 1, or 2 solutions for this example.Where does the non-uniqueness of the solutions lie in the answers we derive?

As it can be seen in the example above, the solutions to an inverse kinematics problem are not necessarily unique. In fact, as the number of degrees of freedom increases, so does the maximum number ofsolutions, as depicted in the figure. It is also possible for a problem to have no solution if the point on the robot cannot be brought to the target point in space at all.

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
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cm
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A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
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Can you compute that for me. Ty
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Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
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A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
Krampah Reply
2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
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you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
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progressive wave
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Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
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Source:  OpenStax, Geometric methods in structural computational biology. OpenStax CNX. Jun 11, 2007 Download for free at http://cnx.org/content/col10344/1.6
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