7.5 Systems of measurement  (Page 9/10)

ⓐ Did you grow up using the U.S. customary or the metric system of measurement? ⓑ Describe two examples in your life when you had to convert between systems of measurement. ⓒ Which system do you think is easier to use? Explain.

$6$

$\mathrm{-5}$

$2.9$

$1.8$

$0.42,0.\stackrel{\text{–}}{\text{3}},\mathrm{2.56813\dots }$

$\text{0.75319…},0.\stackrel{\text{—}}{16},1.95$

ⓐ $\sqrt{49}$ ⓑ $\sqrt{55}$

ⓐ $\sqrt{72}$ ⓑ $\sqrt{64}$

$\mathrm{-9},0,\text{0.361....},\frac{8}{9},\sqrt{16},9$

$\mathrm{-5},-2\frac{1}{4},-\sqrt{4},0.\stackrel{\text{—}}{25},\frac{13}{5},4$

$6+4=\_\_\_\_$

$\mathrm{-14}·5=\_\_\_\_$

$3n=\_\_\_\_$

$a+8=\_\_\_\_$

$(13·5)·2=\_\_\_\_\_$

$(22+7)+3=\_\_\_\_\_$

$(4+9x)+x=\_\_\_\_\_$

$\frac{1}{2}(22y)=\_\_\_\_\_$

If $y=\frac{11}{12},$ evaluate: ⓐ $y+0.7+(-y)$ ⓑ $y+(-y)+0.7$

If $z=-\frac{5}{3},$ evaluate: ⓐ $z+5.39+(-z)$ ⓑ $z+(-z)+5.39$

If $k=65,$ evaluate: ⓐ $\frac{4}{9}\left(\frac{9}{4}k\right)$ ⓑ $(\frac{4}{9}·\frac{9}{4})k$

If $m=\mathrm{-13},$ evaluate: ⓐ $-\frac{2}{5}\left(\frac{5}{2}m\right)$ ⓑ $(-\frac{2}{5}·\frac{5}{2})m$

$6y+37+(\mathrm{-6}y)$

$\frac{1}{4}+\frac{11}{15}+\left(-\frac{1}{4}\right)$

$\frac{14}{11}·\frac{35}{9}·\frac{14}{11}$

$\mathrm{-18}·15·\frac{2}{9}$

$\left(\frac{7}{12}+\frac{4}{5}\right)+\frac{1}{5}$

$\left(3.98d+0.75d\right)+1.25d$

$\mathrm{-12}\left(4m\right)$

$30\left(\frac{5}{6}q\right)$

$11x+8y+16x+15y$

$52m+(\mathrm{-20}n)+(\mathrm{-18}m)+(\mathrm{-5}n)$

$7(x+9)$

$9(u-4)$

$\mathrm{-3}(6m-1)$

$\mathrm{-8}(\mathrm{-7}a-12)$

$\frac{1}{3}(15n-6)$

$(y+10)·p$

$(a-4)-(6a+9)$

$4(x+3)-8(x-7)$

If $u=2,$ evaluate ⓐ $3(8u+9)\text{and}$ ⓑ $3·8u+3·9$ to show that $3(8u+9)=3·8u+3·9$

If $n=\frac{7}{8},$ evaluate ⓐ $8(n+\frac{1}{4})$ and ⓑ $8·n+8·\frac{1}{4}$ to show that $8(n+\frac{1}{4})=8·n+8·\frac{1}{4}$

If $d=14,$ evaluate ⓐ $\mathrm{-100}\left(0.1d+0.35\right)$ and ⓑ $\mathrm{-100}·(0.1d)+\left(\mathrm{-100}\right)\left(0.35\right)$ to show that $\mathrm{-100}\left(0.1d+0.35\right)=\mathrm{-100}·(0.1d)+\left(\mathrm{-100}\right)\left(0.35\right)$

If $y=\mathrm{-18},$ evaluate ⓐ $-\left(y-18\right)$ and ⓑ $-y+18$ to show that $-\left(y-18\right)=-y+18$

$\mathrm{-35}(1)=\mathrm{-35}$

$29+0=29$

$(6x+0)+4x=6x+4x$

$9·1+\left(-3\right)=9+\left(-3\right)$

$\mathrm{-32}$

$19.4$

$\frac{3}{5}$

$-\frac{7}{15}$

$\frac{9}{2}$

$\mathrm{-5}$

$\frac{1}{10}$

$-\frac{4}{9}$

$83·0$

$\frac{0}{9}$

$\frac{5}{0}$

$0÷\frac{2}{3}$

$43+39+(\mathrm{-43})$

$(n+6.75)+0.25$

$\frac{5}{13}·57·\frac{13}{5}$

$\frac{1}{6}·17·12$