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Practice set b

Perform each operation. Simplify when possible.

Add 4 gal 3 qt to 1 gal 2 qt.

6 gal 1 qt

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Add 9 hr 48 min to 4 hr 26 min.

14 hr 14 min

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Subtract 2 ft 5 in. from 8 ft 7 in.

6 ft 2in.

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Subtract 15 km 460 m from 27 km 800 m.

12 km 340 m

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Subtract 8 min 35 sec from 12 min 10 sec.

3 min 35 sec

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Add 4 yd 2 ft 7 in. to 9 yd 2 ft 8 in.

14 yd 2 ft 3 in

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Subtract 11 min 55 sec from 25 min 8 sec.

13 min 13 sec

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Multiplying a denominate number by a whole number

Let's examine the repeated sum

4 ft 9 in. + 4 ft 9 in. + 4 ft 9 in. 3 times = 12 ft 27 in.

Recalling that multiplication is a description of repeated addition, by the distribu­tive property we have

3 ( 4 ft 9 in . ) = 3 ( 4 ft + 9 in. ) = 3 4 ft + 3 9 in. = 12 ft + 27 in. Now, 27 in. = 2 ft 3 in. = 12 ft + 2 ft + 3 in. = 14 ft + 3 in. = 14 ft 3 in.

From these observations, we can suggest the following rule.

Multiplying a denominate number by a whole number

To multiply a denominate number by a whole number, multiply the number part of each unit by the whole number and affix the unit to this product.

Sample set c

Perform the following multiplications. Simplify if necessary.

6 2 ft 4 in. = 6 2 ft + 6 4 in. = 12 ft + 24 in.

Since 3 ft = 1 yd size 12{"3 ft"=" 1 yd"} {} and 12   in . = 1 ft size 12{"12"" in" "." ="1 ft"} {} ,

12 ft + 24 in. = 4 yd + 2 ft = 4 yd 2 ft

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8 5 hr 21 min 55 sec = 8 5 hr + 8 21 min + 8 55 sec = 40 hr + 168 min + 440sec = 40 hr + 168 min + 7 min + 20 sec = 40 hr + 175 min + 20 sec = 40 hr + 2 hr + 55 min + 20 sec = 42 hr + 55 min + 20 sec = 24hr + 18hr + 55 min + 20 sec = 1 da + 18 hr + 55 min + 20 sec = 1 da 18 hr 55 min 20 sec

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Practice set c

Perform the following multiplications. Simplify.

2 10 min size 12{2 cdot left ("10 min" right )} {}

20 min

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5 3 qt size 12{5 cdot left ("3 qt" right )} {}

15 qt = 3 gal 3 qt size 12{"15 qt"="3 gal 3 qt"} {}

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4 5 ft 8 in . size 12{4 cdot left (5" ft 8 in" "." right )} {}

20 ft 32 in . = 7 yd 1 ft 8 in . size 12{"20 ft 32 in" "." =" 7 yd 1 ft 8 in" "." } {}

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10 2 hr 15 min 40 sec size 12{"10" cdot left (2" hr 15 min 40 sec" right )} {}

20 hr 150 min 400 sec = 22 hr 36 min 40 sec size 12{"20 hr 150 min 400 sec"="22 hr 36 min 40 sec"} {}

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Dividing a denominate number by a whole number

Dividing a denominate number by a whole number

To divide a denominate number by a whole number, divide the number part of each unit by the whole number beginning with the largest unit. Affix the unit to this quotient. Carry any remainder to the next unit.

Sample set d

Perform the following divisions. Simplify if necessary.

12 min 40 sec ÷ 4 size 12{ left ("12 min 40 sec" right ) div 4} {}

Long division. 12 min and 40 sec divided by 4. 4 goes into 12 minutes 3 times, making a quotient of 3 minutes with no remainder. 4 goes into 40 seconds 10 times, making a quotient of 10 seconds with no remainder. The total quotient is 3 min 10 sec.

Thus 12 min 40 sec ÷ 4 = 3 min 10 sec size 12{ left ("12 min 40 sec" right ) div 4=3" min 10 sec"} {}

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5 yd 2 ft 9 in . ÷ 3 size 12{ left ("5 yd 2 ft 9 in" "." right ) div 3} {}

Long division. 5 yd 2 ft 9 in divided by 3. 3 goes into 5 yards one time with a remainder of 2 yards. Bring down the 2 feet. 2 yards and 2 feet is eight feet. 3 goes into eight feet twice with a remainder of 2 feet. Bring down the 9 inches. 2 feet 9 in is equal to 22 inches. 3 goes into 33 inches exactly 11 times. The total quotient is 1 yd 2 ft 11 in. Convert to feet: 2 yd 2 ft = 8 ft . Convert to inches: 2 ft 9 in . = 33 in .

Thus 5 yd 2 ft 9 in . ÷ 3 = 1 yd 2 ft 11 in . size 12{ left ("5 yd 2 ft 9 in" "." right ) div 3=1" yd 2 ft 11 in" "." } {}

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Practice set d

Perform the following divisions. Simplify if necessary.

18 hr 36 min ÷ 9 size 12{ left ("18 hr 36 min" right ) div 9} {}

2 hr 4 min

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34 hr 8 min . ÷ 8 size 12{ left ("34 hr 8 min" "." right ) div 8} {}

4 hr 16 min

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13 yd 7 in . ÷ 5 size 12{ left ("13 yd 7 in" "." right ) div 5} {}

2 yd 1 ft 11 in

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47 gal 2 qt 1 pt ÷ 3 size 12{ left ("47 gal 2 qt 1 pt" right ) div 3} {}

15 gal 3 qt 1 pt

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Exercises

For the following 15 problems, simplify the denominate numbers­.

85 min

1 hour 25 minutes

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26 qt

6 gallons 2 quarts

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135 oz

8 pounds 7 ounces

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16,300 mL

16 liters 300 milliliters (or 1daL 6 L 3dL)

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For the following 15 problems, perform the indicated opera­tions and simplify the answers if possible.

Add 6 min 12 sec to 5 min 15 sec.

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Add 14 da 6 hr to 1 da 5 hr.

15 days 11 hours

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Add 9 gal 3 qt to 2 gal 3 qt.

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Add 16 lb 10 oz to 42 lb 15 oz.

59 pounds 9 ounces

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Subtract 3 gal 1 qt from 8 gal 3 qt.

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Subtract 3 ft 10 in. from 5 ft 8 in.

1 foot 10 inches

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Subtract 5 lb 9 oz from 12 lb 5 oz.

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Subtract 10 hr 10 min from 11 hr 28 min.

1 hour 18 minutes

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Add 3 fl oz 1 tbsp 2 tsp to 5 fl oz 1 tbsp 2 tsp.

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Add 4 da 7 hr 12 min to 1 da 8 hr 53 min.

5 days 16 hours 5 minutes

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Subtract 5 hr 21 sec from 11 hr 2 min 14 sec.

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Subtract 6 T 1,300 lb 10 oz from 8 T 400 lb 10 oz.

1 ton 1,100 pounds (or 1T 1,100 lb)

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Subtract 15 mi 10 in. from 27 mi 800 ft 7 in.

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Subtract 3 wk 5 da 50 min 12 sec from 5 wk 6 da 20 min 5 sec.

2 weeks 23 hours 29 minutes 53 seconds

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Subtract 3 gal 3 qt 1 pt 1 oz from 10 gal 2 qt 2 oz.

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Exercises for review

( [link] ) Find the value: 5 8 2 + 39 64 size 12{ left ( { {5} over {8} } right ) rSup { size 8{2} } + { {"39"} over {"64"} } } {} .

1

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( [link] ) Find the sum: 8 + 6 3 5 size 12{8+6 { {3} over {5} } } {} .

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( [link] ) Convert 2 . 05 1 11 size 12{2 "." "05" { {1} over {"11"} } } {} to a fraction.

2 14 275 size 12{2 { {"14"} over {"275"} } } {}

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( [link] ) An acid solution is composed of 3 parts acid to 7 parts water. How many parts of acid are there in a solution that contains 126 parts water?

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( [link] ) Convert 126 kg to grams.

126,000 g

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Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
Aislinn Reply
cm
tijani
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A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
Jude Reply
Can you compute that for me. Ty
Jude
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emma Reply
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what is inorganic
emma
Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
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chemistry could also be understood like the sexual attraction/repulsion of the male and female elements. the reaction varies depending on the energy differences of each given gender. + masculine -female.
Pedro
A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
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2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
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you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
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answer
Magreth
progressive wave
Magreth
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Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
yasuo Reply
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Source:  OpenStax, Fundamentals of mathematics. OpenStax CNX. Aug 18, 2010 Download for free at http://cnx.org/content/col10615/1.4
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