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Mach number

In this exercise we will determine the Mach Number for the different aircraft in the previous table. To help you get started we have calculated the Mach Number for the Concord with a speed of sound v s o u n d = 340 ms - 1 .

For the Condorde we know the speed and we know that:

Mach Number = v aircraft v sound

For the Concorde this means that

Mach Number = 647 340 = 1 . 9
Aircraft speed at altitude ( km · h - 1 ) speed at altitude ( m · s - 1 ) Mach Number
Concorde 2 330 647 1.9
Gripen 2 410 669
Mirage F1 2 573 715
Mig 27 1 885 524
F 15 2 660 739
F 16 2 414 671

Now calculate the Mach Numbers for the other aircraft in the table.

Mach cone

The shape of the Mach Cone depends on the speed of the aircraft. When the Mach Number is 1 there is no cone but as the aircraft goes faster and faster the angle of the cone gets smaller and smaller.

If we go back to the supersonic picture we can work out what the angle of the cone must be.

We build a triangle between how far the plane has moved and how far a wavefront at right angles to the direction the plane is flying has moved:

An aircraft emits a sound wavefront. The wavefront moves at the speed of sound 340 m · s - 1 and the aircraft moves at Mach 1.5, which is 1 . 5 × 340 = 510 m · s - 1 . The aircraft travels faster than the wavefront. If we let the wavefront travel for a time t then the following diagram will apply:

We know how fast the wavefront and the aircraft are moving so we know the distances that they have traveled:

The angle between the cone that forms and the direction of the plane can be found from the right-angle triangle we have drawn into the figure. We know that sin θ = opposite hypotenuse which in this figure means:

sin θ = opposite hypotenuse sin θ = v s o u n d × t v a i r c r a f t × t sin θ = v s o u n d v a i r c r a f t

In this case we have used sound and aircraft but a more general way of saying this is:

  • aircraft = source
  • sound = wavefront

We often just write the equation as:

sin θ = v s o u n d v a i r c r a f t v a i r c r a f t sin θ = v s o u n d v s o u r c e sin θ = v w a v e f r o n t v s sin θ = v w

From this equation, we can see that the faster the source (aircraft) moves, the smaller the angle of the Mach cone.

Mach cone

In this exercise we will determine the Mach Cone Angle for the different aircraft in the table mentioned above. To help you get started we have calculated the Mach Cone Angle for the Concorde with a speed of sound v s o u n d = 340 m · s - 1 .

For the Condorde we know the speed and we know that:

sin θ = v s o u n d v a i r c r a f t

For the Concorde this means that

sin θ = 340 647 θ = sin - 1 340 647 θ = 31 . 7 o
Aircraft speed at altitude ( km · h - 1 ) speed at altitude ( m · s - 1 ) Mach Cone Angle (degrees)
Concorde 2 330 647 31.7
Gripen 2 410 669
Mirage F1 2 573 715
Mig 27 1 885 524
F 15 2 660 739
F 16 2 414 671

Now calculate the Mach Cone Angles for the other aircraft in the table.

End of chapter exercises

  1. In the diagram below the peaks of wavefronts are shown by black lines and the troughs by grey lines. Mark all the points where constructive interference between two waves is taking place and where destructive interference is taking place. Also note whether the interference results in a peak or a trough.
  2. For a slit of width 1300 nm, calculate the first 3 minima for light of the following wavelengths:
    1. blue at 475 nm
    2. green at 510 nm
    3. yellow at 570 nm
    4. red at 650 nm
  3. For light of wavelength 540 nm, determine what the width of the slit needs to be to have the first minimum at:
    1. 7.76 degrees
    2. 12.47 degrees
    3. 21.1 degrees
  4. For light of wavelength 635 nm, determine what the width of the slit needs to be to have the second minimum at:
    1. 12.22 degrees
    2. 18.51 degrees
    3. 30.53 degrees
  5. If the first minimum is at 8.21 degrees and the second minimum is at 16.6 degrees, what is the wavelength of light and the width of the slit? ( Hint: solve simultaneously.)
  6. Determine the Mach Number, with a speed of sound of 340 m · s - 1 , for the following aircraft speeds:
    1. 640 m · s - 1
    2. 980 m · s - 1
    3. 500 m · s - 1
    4. 450 m · s - 1
    5. 1300 km · h - 1
    6. 1450 km · h - 1
    7. 1760 km · h - 1
  7. If an aircraft has a Mach Number of 3.3 and the speed of sound is 340 m · s - 1 , what is its speed?
  8. Determine the Mach Cone angle, with a speed of sound of 340 m · s - 1 , for the following aircraft speeds:
    1. 640 m · s - 1
    2. 980 m · s - 1
    3. 500 m · s - 1
    4. 450 m · s - 1
    5. 1300 km · h - 1
    6. 1450 km · h - 1
    7. 1760 km · h - 1
  9. Determine the aircraft speed, with a speed of sound of 340 m · s - 1 , for the following Mach Cone Angles:
    1. 58.21 degrees
    2. 49.07 degrees
    3. 45.1 degrees
    4. 39.46 degrees
    5. 31.54 degrees

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
Aislinn Reply
cm
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A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
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Can you compute that for me. Ty
Jude
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what is inorganic
emma
Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
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Pedro
A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
Krampah Reply
2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
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you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
Ryan
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answer
Magreth
progressive wave
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Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
yasuo Reply
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Source:  OpenStax, Maths test. OpenStax CNX. Feb 09, 2011 Download for free at http://cnx.org/content/col11236/1.2
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