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Length 19 module: 372 adds / 76 mpys

This module closely follows the traditional Winograd prime-length approach.

  1. Use the index map x ¯ ( n ) = x ( < 2 n > m o d 19 ) to convert the DFT into a length 18 convolution plus a correction term for the DC component.
  2. Reduce the length 16 convolution modulo z 9 + 1 and z 9 - 1 .
    m o d z 9 - 1 : r 100 - r 108 m o d z 9 + 9 : r 109 - r 117
  3. Use Nussbaumer's z 9 - 1 convolution algorithm on r100-r108. This is a transposed tensor method, however it again uses an obscure reconstruction procedure. This algorithm computes nineteen intermediate quantities, r31-r319, which are then weighted against nineteen coefficients to produce t11-t119. This data is then partially reconstructed to yield the final result of the m o d z 9 - 1 convolution, t32-t310.
  4. In the course of the z 9 - 1 convolution algorithm the z 9 - 1 data is reduced modulo z - 1 and stored in r31. This quantity is added to x ( i ( 1 ) ) to patch up the DC term.
  5. An algebraic trick is used to compute the z 9 + 1 convolution using the z 9 - 1 algorithm. Suppose there exists a ring homomorphism H which maps elements of the ring of real polynomials modulo z 9 + 1 into the ring of polynomials modulo z 9 - 1 . Then H could be used on the z 9 + 1 data, the resulting polynomial could be convolved in the modulo z 9 - 1 domain using the existing procedure, and the output of that procedure could be mapped back through H - 1 into the modulo z 9 + 1 domain. Such a homomorphism does exist, and moreover it happens to be its own inverse. H ( p ) where p is a polynomial (in either R [ x ] / z 9 - 1 or R [ x ] / z 9 + 1 ) may be formed from p by negating the sign on all odd-numbered coefficients, that is, H ( p ) ( z ) = p ( - z ) . The alternate negation of data values going into and coming out of the m o d z 9 - 1 convolution algorithm is accomplished without an increase in computing time by appropriate placement of negative signs. The nineteen intermediate values formed are r320-r338 which are then weighted by the (purely imaginary) coefficients to produce t120-t138. A partial reconstruction yields the z 9 + 1 convolution result, t311-t319.
  6. The z 18 - 1 convolution result is reconstructed from the z 9 - 1 (real) and z 9 + 1 (imaginary) vectors and mapped back to the outputs using the reverse of the input map.
  7. All coefficients were computed using the author's QR decomposition linear equation solver and are accurate to at least 14 places.

Length 25 module: 420 adds / 132 mpys

This module is a common factor type module which uses length 5 convolutional DFT submodules. The length 5 submodules are implemented in a transposed tensor configuration using an index map x ( n ¯ ) = x ( < 2 n > m o d 5 ) followed by a reduction modulo all the irreducible factors of z 4 - 1 . The z 2 + 1 convolution is implemented using Toom-Cook factors of z , 1 / z and z - 1 . The reconstruction matrix is exactly the transpose of the reduction procedure. The coefficients for the length 5 submodules were found using the author's QR procedure, and the twiddle factors were generated in a special FORTRAN program. The details of saving multiplies by scaling some of the prime length submodules in a common factor algorithm are discussed below in [link] . This length 25 module has a total of 132 multiplies and 420 adds. Using Winograd's decomposition of the length 25 OFT into two length 5 DFT's and a length 20 convolution the best operation count generated by this author was 108 multiplies and 604 adds.

Questions & Answers

if three forces F1.f2 .f3 act at a point on a Cartesian plane in the daigram .....so if the question says write down the x and y components ..... I really don't understand
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hey , can you please explain oxidation reaction & redox ?
Boitumelo Reply
hey , can you please explain oxidation reaction and redox ?
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for grade 12 or grade 11?
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the value of V1 and V2
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advantages of electrons in a circuit
Rethabile Reply
we're do you find electromagnetism past papers
Ntombifuthi
what a normal force
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it is the force or component of the force that the surface exert on an object incontact with it and which acts perpendicular to the surface
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what is the half reaction of Potassium and chlorine
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how to calculate coefficient of static friction
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how to calculate static friction
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How to calculate a current
Tumelo
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How to calculate force
Monambi
a structure of a thermocouple used to measure inner temperature
Anna Reply
a fixed gas of a mass is held at standard pressure temperature of 15 degrees Celsius .Calculate the temperature of the gas in Celsius if the pressure is changed to 2×10 to the power 4
Amahle Reply
How is energy being used in bonding?
Raymond Reply
what is acceleration
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a rate of change in velocity of an object whith respect to time
Khuthadzo
how can we find the moment of torque of a circular object
Kidist
Acceleration is a rate of change in velocity.
Justice
t =r×f
Khuthadzo
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Precious Reply
hi
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Leago
use fnet method. how many obects are being calculated ?
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Lungile Reply
you use Fnet equals ma , newtoms second law formula
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Source:  OpenStax, Large dft modules: 11, 13, 16, 17, 19, and 25. revised ece technical report 8105. OpenStax CNX. Sep 14, 2009 Download for free at http://cnx.org/content/col10569/1.7
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