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The Fundamental Theorem of Calculus gave us a method to evaluate integrals without using Riemann sums. The drawback of this method, though, is that we must be able to find an antiderivative, and this is not always easy. In this section we examine a technique, called integration by substitution , to help us find antiderivatives. Specifically, this method helps us find antiderivatives when the integrand is the result of a chain-rule derivative.
At first, the approach to the substitution procedure may not appear very obvious. However, it is primarily a visual task—that is, the integrand shows you what to do; it is a matter of recognizing the form of the function. So, what are we supposed to see? We are looking for an integrand of the form For example, in the integral we have and Then,
and we see that our integrand is in the correct form.
The method is called substitution because we substitute part of the integrand with the variable u and part of the integrand with du . It is also referred to as change of variables because we are changing variables to obtain an expression that is easier to work with for applying the integration rules.
Let where is continuous over an interval, let be continuous over the corresponding range of g , and let be an antiderivative of Then,
Let f , g , u , and F be as specified in the theorem. Then
Integrating both sides with respect to x , we see that
If we now substitute and we get
□
Returning to the problem we looked at originally, we let and then Rewrite the integral in terms of u :
Using the power rule for integrals, we have
Substitute the original expression for x back into the solution:
We can generalize the procedure in the following Problem-Solving Strategy.
Use substitution to find the antiderivative of
The first step is to choose an expression for u . We choose because then and we already have du in the integrand. Write the integral in terms of u :
Remember that du is the derivative of the expression chosen for u , regardless of what is inside the integrand. Now we can evaluate the integral with respect to u :
Analysis
We can check our answer by taking the derivative of the result of integration. We should obtain the integrand. Picking a value for C of 1, we let We have
so
This is exactly the expression we started with inside the integrand.
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