Explanation:
The first step here is to calculate Re for the corresponding flow in a straight pipe. Here, it is about 80,000. Hence, the flow is fully turbulent. Then, we may follow the calculation procedure as set forth in the Roymech resource on "Fluid Flow in Pipes" cited in Unit 4 or another like it. There is no need to memorize such procedures, but you should be familiar with following them. For the case here, we find v = 6.6 m/s, fT = 0.027, and K = 0.81. Hence, the pressure drop associated with the fitting is approximately 0.81 * v2/2 * r = 17.5 kPa.
