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Third, the probability density distributions | ψ n ( x ) | 2 for a quantum oscillator in the ground low-energy state, ψ 0 ( x ) , is largest at the middle of the well ( x = 0 ) . For the particle to be found with greatest probability at the center of the well, we expect that the particle spends the most time there as it oscillates. This is opposite to the behavior of a classical oscillator, in which the particle spends most of its time moving with relative small speeds near the turning points.

Check Your Understanding Find the expectation value of the position for a particle in the ground state of a harmonic oscillator using symmetry.

x = 0

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Quantum probability density distributions change in character for excited states, becoming more like the classical distribution when the quantum number gets higher. We observe this change already for the first excited state of a quantum oscillator because the distribution | ψ 1 ( x ) | 2 peaks up around the turning points and vanishes at the equilibrium position, as seen in [link] . In accordance with Bohr’s correspondence principle, in the limit of high quantum numbers, the quantum description of a harmonic oscillator converges to the classical description, which is illustrated in [link] . The classical probability density distribution corresponding to the quantum energy of the n = 12 state is a reasonably good approximation of the quantum probability distribution for a quantum oscillator in this excited state. This agreement becomes increasingly better for highly excited states.

The probability density distribution amplitude squared of Psi sub 12 for the quantum harmonic oscillator is plotted as a function of x as a solid curve. The curve has 13 peaks with 12 zeros between them and goes asymptotically to zero at plus and minus infinity. The amplitude of the peaks is lowest at the center and increases wit distance from the origin. All of the peaks are between x=-A and x=+A. The dashed curve which shows the probability density distribution of a classical oscillator with the same energy is a smooth upward opening curve.
The probability density distribution for finding the quantum harmonic oscillator in its n = 12 quantum state. The dashed curve shows the probability density distribution of a classical oscillator with the same energy.

Summary

  • The quantum harmonic oscillator is a model built in analogy with the model of a classical harmonic oscillator. It models the behavior of many physical systems, such as molecular vibrations or wave packets in quantum optics.
  • The allowed energies of a quantum oscillator are discrete and evenly spaced. The energy spacing is equal to Planck’s energy quantum.
  • The ground state energy is larger than zero. This means that, unlike a classical oscillator, a quantum oscillator is never at rest, even at the bottom of a potential well, and undergoes quantum fluctuations.
  • The stationary states (states of definite energy) have nonzero values also in regions beyond classical turning points. When in the ground state, a quantum oscillator is most likely to be found around the position of the minimum of the potential well, which is the least-likely position for a classical oscillator.
  • For high quantum numbers, the motion of a quantum oscillator becomes more similar to the motion of a classical oscillator, in accordance with Bohr’s correspondence principle.

Conceptual questions

Is it possible to measure energy of 0.75 ω for a quantum harmonic oscillator? Why? Why not? Explain.

No. This energy corresponds to n = 0.25 , but n must be an integer.

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Explain the connection between Planck’s hypothesis of energy quanta and the energies of the quantum harmonic oscillator.

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If a classical harmonic oscillator can be at rest, why can the quantum harmonic oscillator never be at rest? Does this violate Bohr’s correspondence principle?

Because the smallest allowed value of the quantum number n for a simple harmonic oscillator is 0. No, because quantum mechanics and classical mechanics agree only in the limit of large n .

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Use an example of a quantum particle in a box or a quantum oscillator to explain the physical meaning of Bohr’s correspondence principle.

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Can we simultaneously measure position and energy of a quantum oscillator? Why? Why not?

Yes, within the constraints of the uncertainty principle. If the oscillating particle is localized, the momentum and therefore energy of the oscillator are distributed.

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Problems

Show that the two lowest energy states of the simple harmonic oscillator, ψ 0 ( x ) and ψ 1 ( x ) from [link] , satisfy [link] .

proof

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If the ground state energy of a simple harmonic oscillator is 1.25 eV, what is the frequency of its motion?

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When a quantum harmonic oscillator makes a transition from the ( n + 1 ) state to the n state and emits a 450-nm photon, what is its frequency?

6.662 × 10 14 Hz

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Vibrations of the hydrogen molecule H 2 can be modeled as a simple harmonic oscillator with the spring constant k = 1.13 × 10 3 N / m and mass m = 1.67 × 10 −27 kg . (a) What is the vibrational frequency of this molecule? (b) What are the energy and the wavelength of the emitted photon when the molecule makes transition between its third and second excited states?

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A particle with mass 0.030 kg oscillates back-and-forth on a spring with frequency 4.0 Hz. At the equilibrium position, it has a speed of 0.60 m/s. If the particle is in a state of definite energy, find its energy quantum number.

n 2.037 × 10 30

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Find the expectation value x 2 of the square of the position for a quantum harmonic oscillator in the ground state. Note: + d x x 2 e a x 2 = π ( 2 a 3 / 2 ) 1 .

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Determine the expectation value of the potential energy for a quantum harmonic oscillator in the ground state. Use this to calculate the expectation value of the kinetic energy.

x = 0.5 m ω 2 x 2 = ω / 4 ; K = E U = ω / 4

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Verify that ψ 1 ( x ) given by [link] is a solution of Schrӧdinger’s equation for the quantum harmonic oscillator.

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Estimate the ground state energy of the quantum harmonic oscillator by Heisenberg’s uncertainty principle. Start by assuming that the product of the uncertainties Δ x and Δ p is at its minimum. Write Δ p in terms of Δ x and assume that for the ground state x Δ x and p Δ p , then write the ground state energy in terms of x . Finally, find the value of x that minimizes the energy and find the minimum of the energy.

proof

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A mass of 0.250 kg oscillates on a spring with the force constant 110 N/m. Calculate the ground energy level and the separation between the adjacent energy levels. Express the results in joules and in electron-volts. Are quantum effects important?

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Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
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cm
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A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
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Can you compute that for me. Ty
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what is inorganic
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Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
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chemistry could also be understood like the sexual attraction/repulsion of the male and female elements. the reaction varies depending on the energy differences of each given gender. + masculine -female.
Pedro
A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
Krampah Reply
2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
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you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
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progressive wave
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Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
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Source:  OpenStax, University physics volume 3. OpenStax CNX. Nov 04, 2016 Download for free at http://cnx.org/content/col12067/1.4
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