<< Chapter < Page Chapter >> Page >

Two thin parallel conducting plates are placed 2.0 cm apart. Each plate is 2.0 cm on a side; one plate carries a net charge of 8.0 μ C , and the other plate carries a net charge of −8.0 μ C . What is the charge density on the inside surface of each plate? What is the electric field between the plates?

σ = 0.02 C / m 2 E = 2.26 × 10 9 N / C

Got questions? Get instant answers now!

A thin conducing plate 2.0 m on a side is given a total charge of −10.0 μ C . (a) What is the electric field 1.0 cm above the plate? (b) What is the force on an electron at this point? (c) Repeat these calculations for a point 2.0 cm above the plate. (d) When the electron moves from 1.0 to 2,0 cm above the plate, how much work is done on it by the electric field?

Got questions? Get instant answers now!

A total charge q is distributed uniformly along a thin, straight rod of length L (see below). What is the electric field at P 1 ? At P 2 ?

A horizontal rod of length L is shown. The rod has total charge q. Point P 1 is a distance a over 2 above the midpoint of the rod, so that the horizontal distance from P 1 to each end of the rod is L over 2. Point P 2 is a distance a to the right of the right end of the rod.

At P 1 : E ( y ) = 1 4 π ε 0 λ L y y 2 + L 2 4 j ^ 1 4 π ε 0 q a 2 ( a 2 ) 2 + L 2 4 j ^ = 1 π ε 0 q a a 2 + L 2 j ^
At P 2 : Put the origin at the end of L .
d E = 1 4 π ε 0 λ d x ( x + a ) 2 , E = q 4 π ε 0 l [ 1 l + a 1 a ] i ^

Got questions? Get instant answers now!

Charge is distributed along the entire x -axis with uniform density λ . How much work does the electric field of this charge distribution do on an electron that moves along the y -axis from y = a to y = b ?

Got questions? Get instant answers now!

Charge is distributed along the entire x -axis with uniform density λ x and along the entire y -axis with uniform density λ y . Calculate the resulting electric field at (a) r = a i ^ + b j ^ and (b) r = c k ^ .

a. E ( r ) = 1 4 π ε 0 2 λ x a i ^ + 1 4 π ε 0 2 λ y b j ^ ; b. 1 4 π ε 0 2 ( λ x + λ y ) c k ^

Got questions? Get instant answers now!

A rod bent into the arc of a circle subtends an angle 2 θ at the center P of the circle (see below). If the rod is charged uniformly with a total charge Q , what is the electric field at P ?

An arc that is part of a circle of radius R and with center P is shown. The arc extends from an angle theta to the left of vertical to an angle theta to the right of vertical.
Got questions? Get instant answers now!

A proton moves in the electric field E = 200 i ^ N/C . (a) What are the force on and the acceleration of the proton? (b) Do the same calculation for an electron moving in this field.

a. F = 3.2 × 10 −17 N i ^ ,
a = 1.92 × 10 10 m / s 2 i ^ ;
b. F = −3.2 × 10 −17 N i ^ ,
a = −3.51 × 10 13 m / s 2 i ^

Got questions? Get instant answers now!

An electron and a proton, each starting from rest, are accelerated by the same uniform electric field of 200 N/C. Determine the distance and time for each particle to acquire a kinetic energy of 3.2 × 10 −16 J .

Got questions? Get instant answers now!

A spherical water droplet of radius 25 μ m carries an excess 250 electrons. What vertical electric field is needed to balance the gravitational force on the droplet at the surface of the earth?

m = 6.5 × 10 −11 kg ,
E = 1.6 × 107 N / C

Got questions? Get instant answers now!

A proton enters the uniform electric field produced by the two charged plates shown below. The magnitude of the electric field is 4.0 × 10 5 N/C , and the speed of the proton when it enters is 1.5 × 10 7 m/s . What distance d has the proton been deflected downward when it leaves the plates?

Two oppositely charged horizontal plates are parallel to each other. The upper plate is positive and the lower is negative. The plates are 12.0 centimeters long. The path of a positive proton is shown passing from left to right between the plates. It enters moving horizontally and deflects down toward the negative plate, emerging a distance d below the straight line trajectory.
Got questions? Get instant answers now!

Shown below is a small sphere of mass 0.25 g that carries a charge of 9.0 × 10 −10 C . The sphere is attached to one end of a very thin silk string 5.0 cm long. The other end of the string is attached to a large vertical conducting plate that has a charge density of 30 × 10 −6 C/m 2 . What is the angle that the string makes with the vertical?

A small sphere is attached to the lower end of a string. The other end of the string is attached to a large vertical conducting plate that has a uniform positive charge density. The string makes an angle of theta with the vertical.

E = 1.70 × 10 6 N / C ,
F = 1.53 × 10 −3 N T cos θ = m g T sin θ = q E ,
tan θ = 0.62 θ = 32.0 ° ,
This is independent of the length of the string.

Got questions? Get instant answers now!

Two infinite rods, each carrying a uniform charge density λ , are parallel to one another and perpendicular to the plane of the page. (See below.) What is the electrical field at P 1 ? At P 2 ?

An end view of the arrangement in the problem is shown. Two rods are parallel to one another and perpendicular to the plane of the page. They are separated by a horizontal distance of a. Pint P 1 is a distance of a over 2 above the midpoint between the rods, and so also a distance of a over 2 horizontally from each rod. Point P 2 is a distance of a to the right of the rightmost rod.
Got questions? Get instant answers now!

Positive charge is distributed with a uniform density λ along the positive x -axis from r to , along the positive y -axis from r to , and along a 90 ° arc of a circle of radius r , as shown below. What is the electric field at O ?

A uniform distribution of positive charges is shown on an x y coordinate system. The charges are distributed along a 90 degree arc of a circle of radius r in the first quadrant, centered on the origin. The distribution continues along the positive x and y axes from r to infinity.

circular arc d E x ( i ^ ) = 1 4 π ε 0 λ d s r 2 cos θ ( i ^ ) ,
E x = λ 4 π ε 0 r ( i ^ ) ,
d E y ( i ^ ) = 1 4 π ε 0 λ d s r 2 sin θ ( j ^ ) ,
E y = λ 4 π ε 0 r ( j ^ ) ;
y -axis: E x = λ 4 π ε 0 r ( i ^ ) ;
x -axis: E y = λ 4 π ε 0 r ( j ^ ) ,
E = λ 2 π ε 0 r ( i ^ ) + λ 2 π ε 0 r ( j ^ )

Got questions? Get instant answers now!

From a distance of 10 cm, a proton is projected with a speed of v = 4.0 × 10 6 m/s directly at a large, positively charged plate whose charge density is σ = 2.0 × 10 −5 C/m 2 . (See below.) (a) Does the proton reach the plate? (b) If not, how far from the plate does it turn around?

A positive charge is shown at a distance of 10 centimeters and moving to the right with a speed of 4.0 times 10 to the 6 meters per second, directly toward a large, positively and uniformly charged vertical plate.
Got questions? Get instant answers now!

A particle of mass m and charge q moves along a straight line away from a fixed particle of charge Q . When the distance between the two particles is r 0 , q is moving with a speed v 0 . (a) Use the work-energy theorem to calculate the maximum separation of the charges. (b) What do you have to assume about v 0 to make this calculation? (c) What is the minimum value of v 0 such that q escapes from Q ?

a. W = 1 2 m ( v 2 v 0 2 ) , Q q 4 π ε 0 ( 1 r 1 r 0 ) = 1 2 m ( v 2 v 0 2 ) r 0 r = 4 π ε 0 Q q 1 2 r r 0 m ( v 2 v 0 2 ) ; b. r 0 r is negative; therefore, v 0 > v , r , and v 0 : Q q 4 π ε 0 ( 1 r 0 ) = 1 2 m v 0 2 v 0 = Q q 2 π ε 0 m r 0

Got questions? Get instant answers now!
Practice Key Terms 6

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, University physics volume 2. OpenStax CNX. Oct 06, 2016 Download for free at http://cnx.org/content/col12074/1.3
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'University physics volume 2' conversation and receive update notifications?

Ask