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By the end of this section you will be able to:
  • Describe the meaning of entropy
  • Calculate the change of entropy for some simple processes

The second law of thermodynamics is best expressed in terms of a change in the thermodynamic variable known as entropy    , which is represented by the symbol S . Entropy, like internal energy, is a state function. This means that when a system makes a transition from one state into another, the change in entropy Δ S is independent of path and depends only on the thermodynamic variables of the two states.

We first consider Δ S for a system undergoing a reversible process at a constant temperature. In this case, the change in entropy of the system is given by

Δ S = Q T ,

where Q is the heat exchanged by the system kept at a temperature T (in kelvin). If the system absorbs heat—that is, with Q > 0 —the entropy of the system increases. As an example, suppose a gas is kept at a constant temperature of 300 K while it absorbs 10 J of heat in a reversible process. Then from [link] , the entropy change of the gas is

Δ S = 10 J 300 K = 0.033 J/K .

Similarly, if the gas loses 5.0 J of heat; that is, Q = −5.0 J , at temperature T = 200 K , we have the entropy change of the system given by

Δ S = −5.0 J 200 K = −0.025 J/K .

Entropy change of melting ice

Heat is slowly added to a 50-g chunk of ice at 0 ° C until it completely melts into water at the same temperature. What is the entropy change of the ice?

Strategy

Because the process is slow, we can approximate it as a reversible process. The temperature is a constant, and we can therefore use [link] in the calculation.

Solution

The ice is melted by the addition of heat:

Q = m L f = 50 g × 335 J/g = 16.8 kJ .

In this reversible process, the temperature of the ice-water mixture is fixed at 0 °C or 273 K. Now from Δ S = Q / T , the entropy change of the ice is

Δ S = 16.8 kJ 273 K = 61.5 J/K

when it melts to water at 0 °C .

Significance

During a phase change, the temperature is constant, allowing us to use [link] to solve this problem. The same equation could also be used if we changed from a liquid to a gas phase, since the temperature does not change during that process either.

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The change in entropy of a system for an arbitrary, reversible transition for which the temperature is not necessarily constant is defined by modifying Δ S = Q / T . Imagine a system making a transition from state A to B in small, discrete steps. The temperatures associated with these states are T A and T B , respectively. During each step of the transition, the system exchanges heat Δ Q i reversibly at a temperature T i . This can be accomplished experimentally by placing the system in thermal contact with a large number of heat reservoirs of varying temperatures T i , as illustrated in [link] . The change in entropy for each step is Δ S i = Q i / T i . The net change in entropy of the system for the transition is

Δ S = S B S A = i Δ S i = i Δ Q i T i .

We now take the limit as Δ Q i 0 , and the number of steps approaches infinity. Then, replacing the summation by an integral, we obtain

Δ S = S B S A = A B d Q T ,

where the integral is taken between the initial state A and the final state B . This equation is valid only if the transition from A to B is reversible.

Questions & Answers

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Source:  OpenStax, University physics volume 2. OpenStax CNX. Oct 06, 2016 Download for free at http://cnx.org/content/col12074/1.3
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