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Check Your Understanding A Carnot engine operates between reservoirs at 400 °C and 30 °C . (a) What is the efficiency of the engine? (b) If the engine does 5.0 J of work per cycle, how much heat per cycle does it absorb from the high-temperature reservoir? (c) How much heat per cycle does it exhaust to the cold-temperature reservoir? (d) What temperatures at the cold reservoir would give the minimum and maximum efficiency?

a. e = 1 T c / T h = 0.55 ; b. Q h = e W = 9.1 J ; c. Q c = Q h W = 4.1 J ; d. −273 ° C and 400 ° C

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Check Your Understanding A Carnot refrigerator operates between two heat reservoirs whose temperatures are 0 ° C and 25 ° C . (a) What is the coefficient of performance of the refrigerator? (b) If 200 J of work are done on the working substance per cycle, how much heat per cycle is extracted from the cold reservoir? (c) How much heat per cycle is discarded to the hot reservoir?

a. K R = T c / ( T h T c ) = 10.9 ; b. Q c = K R W = 2.18 kJ ; c. Q h = Q c + W = 2.38 kJ

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Summary

  • The Carnot cycle is the most efficient engine for a reversible cycle designed between two reservoirs.
  • The Carnot principle is another way of stating the second law of thermodynamics.

Conceptual questions

To increase the efficiency of a Carnot engine, should the temperature of the hot reservoir be raised or lowered? What about the cold reservoir?

In order to increase the efficiency, the temperature of the hot reservoir should be raised, and the cold reservoir should be lowered as much as possible. This can be seen in [link] .

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How could you design a Carnot engine with 100 % efficiency?

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What type of processes occur in a Carnot cycle?

adiabatic and isothermal processes

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Problems

The temperature of the cold and hot reservoirs between which a Carnot refrigerator operates are −73 ° C and 270 °C , respectively. Which is its coefficient of performance?

2.0

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Suppose a Carnot refrigerator operates between T c and T h . Calculate the amount of work required to extract 1.0 J of heat from the cold reservoir if (a) T c = 7 ° C , T h = 27 ° C ; (b) T c = −73 ° C , T h = 27 ° C; (c) T c = −173 ° C , T h = 27 ° C ; and (d) T c = −273 ° C , T h = 27 ° C .

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A Carnot engine operates between reservoirs at 600 and 300 K. If the engine absorbs 100 J per cycle at the hot reservoir, what is its work output per cycle?

50 J

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A 500-W motor operates a Carnot refrigerator between −5 ° C and 30 °C . (a) What is the amount of heat per second extracted from the inside of the refrigerator? (b) How much heat is exhausted to the outside air per second?

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Sketch a Carnot cycle on a temperature-volume diagram.


The graph shows isotherms and adiabatic curves for Carnot cycle with four points A, B, C and D. The x-axis is V and y-axis is T. The value of T at A and B is T subscript 1 and at C and D is T subscript 2.

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A Carnot heat pump operates between 0 °C and 20 °C . How much heat is exhausted into the interior of a house for every 1.0 J of work done by the pump?

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An engine operating between heat reservoirs at 20 ° C and 200 ° C extracts 1000 J per cycle from the hot reservoir. (a) What is the maximum possible work that engine can do per cycle? (b) For this maximum work, how much heat is exhausted to the cold reservoir per cycle?

a. 900 J; b. 100 J

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Suppose a Carnot engine can be operated between two reservoirs as either a heat engine or a refrigerator. How is the coefficient of performance of the refrigerator related to the efficiency of the heat engine?

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A Carnot engine is used to measure the temperature of a heat reservoir. The engine operates between the heat reservoir and a reservoir consisting of water at its triple point. (a) If 400 J per cycle are removed from the heat reservoir while 200 J per cycle are deposited in the triple-point reservoir, what is the temperature of the heat reservoir? (b) If 400 J per cycle are removed from the triple-point reservoir while 200 J per cycle are deposited in the heat reservoir, what is the temperature of the heat reservoir?

a. 546 K; b. 137 K

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What is the minimum work required of a refrigerator if it is to extract 50 J per cycle from the inside of a freezer at −10 °C and exhaust heat to the air at 25 °C ?

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Source:  OpenStax, University physics volume 2. OpenStax CNX. Oct 06, 2016 Download for free at http://cnx.org/content/col12074/1.3
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