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A graph of the molar heat capacity C V in joules per mole Kelvin as a function of temperature in Kelvin. The horizontal scale is logarithmic and extends from 10 to 10,000. The vertical scale is linear and extends from 10 to 30. The graph shows three steps. The first extends from about 20 K to 50 K at a constant value of about 12.5 Joules per Mole Kelvin. This step is labeled three halves R. The graph rises gradually to another step that extends from about 300 K to about 500 K at a constant value of about 20 Joules per Mole Kelvin. This step is labeled five halves R. The graph again rises gradually and flattens to start a third step at around 3000 K at a constant value of just under 30 Joules per Mole Kelvin. This step is labeled seven halves R.
The molar heat capacity of hydrogen as a function of temperature (on a logarithmic scale). The three “steps” or “plateaus” show different numbers of degrees of freedom that the typical energies of molecules must achieve to activate. Translational kinetic energy corresponds to three degrees of freedom, rotational to another two, and vibrational to yet another two.

Polyatomic molecules typically have one additional rotational degree of freedom at room temperature, since they have comparable moments of inertia around any axis. Thus, at room temperature, they have d = 6 , and at high temperature, d = 8 . We usually assume that gases have the theoretical room-temperature values of d .

As shown in [link] , the results agree well with experiments for many monatomic and diatomic gases, but the agreement for triatomic gases is only fair. The differences arise from interactions that we have ignored between and within molecules.

C V / R For various monatomic, diatomic, and triatomic gases
Gas C V / R at 25 °C and 1 atm
Ar 1.50
He 1.50
Ne 1.50
CO 2.50
H 2 2.47
N 2 2.50
O 2 2.53
F 2 2.8
CO 2 3.48
H 2 S 3.13
N 2 O 3.66

What about internal energy for diatomic and polyatomic gases? For such gases, C V is a function of temperature ( [link] ), so we do not have the kind of simple result we have for monatomic ideal gases.

Molar heat capacity of solid elements

The idea of equipartition leads to an estimate of the molar heat capacity of solid elements at ordinary temperatures. We can model the atoms of a solid as attached to neighboring atoms by springs ( [link] ).

The figure is an illustration of a model of a solid. Seven atoms, one at the center and one on either side, above, below, in front and behind it, are represented as small spheres. The center atom is connected to each of the others by a spring, labeled as ideal springs. The neighboring atoms have additional springs to connect them to their nearest neighbors, which are not included in the drawing.
In a simple model of a solid element, each atom is attached to others by six springs, two for each possible motion: x , y , and z . Each of the three motions corresponds to two degrees of freedom, one for kinetic energy and one for potential energy. Thus d = 6 .

Analogously to the discussion of vibration in the previous module, each atom has six degrees of freedom: one kinetic and one potential for each of the x -, y -, and z -directions. Accordingly, the molar specific heat of a metal should be 3 R . This result, known as the Law of Dulong and Petit , works fairly well experimentally at room temperature. (For every element, it fails at low temperatures for quantum-mechanical reasons. Since quantum effects are particularly important for low-mass particles, the Law of Dulong and Petit already fails at room temperature for some light elements, such as beryllium and carbon. It also fails for some heavier elements for various reasons beyond what we can cover.)

Problem-solving strategy: heat capacity and equipartition

The strategy for solving these problems is the same as the one in Phase Changes for the effects of heat transfer. The only new feature is that you should determine whether the case just presented—ideal gases at constant volume—applies to the problem. (For solid elements, looking up the specific heat capacity is generally better than estimating it from the Law of Dulong and Petit.) In the case of an ideal gas, determine the number d of degrees of freedom from the number of atoms in the gas molecule and use it to calculate C V (or use C V to solve for d ).

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Source:  OpenStax, University physics volume 2. OpenStax CNX. Oct 06, 2016 Download for free at http://cnx.org/content/col12074/1.3
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