<< Chapter < Page Chapter >> Page >

The equilibrium constant

Equilibrium constant

The equilibrium constant (K c ), relates to a chemical reaction at equilibrium. It can be calculated if the equilibrium concentration of each reactant and product in a reaction at equilibrium is known.

Calculating the equilibrium constant

Consider the following generalised reaction which takes place in a closed container at a constant temperature :

A + B C + D

We know from "Factors affecting reaction rates" that the rate of the forward reaction is directly proportional to the concentration of the reactants. In other words, as the concentration of the reactants increases, so does the rate of the forward reaction. This can be shown using the following equation:

Rate of forward reaction [A][B]

or

Rate of forward reaction = k 1 [A][B]

Similarly, the rate of the reverse reaction is directly proportional to the concentration of the products. This can be shown using the following equation:

Rate of reverse reaction [C][D]

or

Rate of reverse reaction = k 2 [C][D]

At equilibrium, the rate of the forward reaction is equal to the rate of the reverse reaction. This can be shown using the following equation:

k 1 [ A ] [ B ] = k 2 [ C ] [ D ]

or

k 1 k 2 = [ C ] [ D ] [ A ] [ B ]

or, if the constants k 1 and k 2 are simplified to a single constant, the equation becomes:

k c = [ C ] [ D ] [ A ] [ B ]

A more general form of the equation for a reaction at chemical equilibrium is:

a A + b B c C + d D

where A and B are reactants, C and D are products and a, b, c, and d are the coefficients of the respective reactants and products. A more general formula for calculating the equilibrium constant is therefore:

K c = [ C ] c [ D ] d [ A ] a [ B ] b

It is important to note that if a reactant or a product in a chemical reaction is in either the liquid or solid phase, the concentration stays constant during the reaction. Therefore, these values can be left out of the equation to calculate K c . For example, in the following reaction:

C ( s ) + H 2 O ( g ) C O ( g ) + H 2 ( g )

K c = [ C O ] [ H 2 ] [ H 2 O ]
  1. The constant K c is affected by temperature and so, if the values of K c are being compared for different reactions, it is important that all the reactions have taken place at the same temperature.
  2. K c values do not have units. If you look at the equation, the units all cancel each other out.

The meaning of k c Values

The formula for K c has the concentration of the products in the numerator and the concentration of reactants in the denominator. So a high K c value means that the concentration of products is high and the reaction has a high yield. We can also say that the equilibrium lies far to the right. The opposite is true for a low K c value. A low K c value means that, at equilibrium, there are more reactants than products and therefore the yield is low. The equilibrium for the reaction lies far to the left.

Calculations made easy

When you are busy with calculations that involve the equilibrium constant, the following tips may help:

  1. Make sure that you always read the question carefully to be sure of what you are being asked to calculate. If the equilibrium constant is involved, make sure that the concentrations you use are the concentrations at equilibrium , and not the concentrations or quantities that are present at some other time in the reaction.
  2. When you are doing more complicated calculations, it sometimes helps to draw up a table like the one below and fill in the mole values that you know or those you can calculate. This will give you a clear picture of what is happening in the reaction and will make sure that you use the right values in your calculations.
    Reactant 1 Reactant 2 Product 1
    Start of reaction
    Used up
    Produced
    Equilibrium

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, Siyavula textbooks: grade 12 physical science. OpenStax CNX. Aug 03, 2011 Download for free at http://cnx.org/content/col11244/1.2
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Siyavula textbooks: grade 12 physical science' conversation and receive update notifications?

Ask