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1 mole of nitrogen (N 2 ) reacts with hydrogen (H 2 ) according to the following equation:

N 2 + 3 H 2 2 N H 3

The ammonia (NH 3 ) gas is collected in a separate gas cylinder which has a volume of 25 dm 3 . The temperature of the gas is 22 C. Calculate the pressure of the gas inside the cylinder.

  1. V = 25 dm 3

    n = 2 (Calculate this by looking at the mole ratio of nitrogen to ammonia, which is 1:2)

    T = 22 C

  2. V = 25 1000 = 0 . 025 m 3
    T = 22 + 273 = 295 K
  3. p V = n R T

    Therefore,

    p = n R T V
  4. p = 2 × 8 . 3 × 295 0 . 025 = 195880 P a = 195 . 89 k P a
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Calculate the number of moles of air particles in a 10 m by 7 m by 2 m classroom on a day when the temperature is 23 C and the air pressure is 98 kPa.

  1. V = 10 m × 7 m × 2m = 140 m 3

    p = 98 kPa

    T = 23 C

  2. p = 98 × 1000 = 98000 P a
    T = 23 + 273 = 296 K
  3. p V = n R T

    Therefore,

    n = p V R T
  4. n = 98 000 × 140 8 . 3 × 296 = 5584 . 5 m o l
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Most modern cars are equipped with airbags for both the driver and the passenger. An airbag will completely inflate in 0,05 s. This is important because a typical car collision lasts about 0,125 s. The following reaction of sodium azide (a compound found in airbags) is activated by an electrical signal:

2 N a N 3 ( s ) 2 N a ( s ) + 3 N 2 ( g )

  1. Calculate the mass of N 2 ( g ) needed to inflate a sample airbag to a volume of 65 dm 3 at 25 C and 99 , 3 kPa. Assume the gas temperature remains constant during the reaction.
  2. In reality the above reaction is exothermic. Describe, in terms of the kinetic molecular theory, how the pressure in the sample airbag will change, if at all, as the gas temperature returns to 25 C.
  1. Here you are given the volume, temperature and pressure. You are required to work out the mass of N 2 .

  2. Pressure: 93 . 3 × 10 3 Pa

    Volume: 65 × 10 - 3 m 3

    Temperature: ( 273 + 25 ) K

    Gas Constant: 8 , 31 J . K - 1 . m o l - 1

  3. p V = n R T
  4. n = p V R T
  5. n = ( 99 , 3 × 10 3 ) × ( 65 × 10 - 3 ) 8 , 31 × ( 273 + 25 )
  6. m = n × M m = 2 , 61 × 28 m = 73 , 0 g
  7. When the temperature decreases the intensity of collisions with the walls of the airbag and between particles decreases. Therefore pressure decreases.

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The ideal gas equation

  1. An unknown gas has pressure, volume and temperature of 0.9 atm, 8 L and 120 C respectively. How many moles of gas are present?
  2. 6 g of chlorine (Cl 2 ) occupies a volume of 0.002 m 3 at a temperature of 26 C. What is the pressure of the gas under these conditions?
  3. An average pair of human lungs contains about 3.5 L of air after inhalation and about 3.0 L after exhalation. Assuming that air in your lungs is at 37 C and 1.0 atm, determine the number of moles of air in a typical breath.
  4. A learner is asked to calculate the answer to the problem below: Calculate the pressure exerted by 1.5 moles of nitrogen gas in a container with a volume of 20 dm 3 at a temperature of 37 C. The learner writes the solution as follows: V = 20 dm 3 n = 1.5 mol R = 8.3 J.K - 1 .mol - 1 T = 37 + 273 = 310 K pT = nRV, therefore
    p = n R V T = 1 . 5 × 8 . 3 × 20 310 = 0 . 8 k P a
    1. Identify 2 mistakes the learner has made in the calculation.
    2. Are the units of the final answer correct?
    3. Rewrite the solution, correcting the mistakes to arrive at the right answer.

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Source:  OpenStax, Siyavula textbooks: grade 11 physical science. OpenStax CNX. Jul 29, 2011 Download for free at http://cnx.org/content/col11241/1.2
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