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How to compute discrete-time Fourier transforms for decaying sequences.

Let's compute the discrete-time Fourier transform of the exponentially decaying sequence s n a n u n , where u n is the unit-step sequence. Simply plugging the signal's expression into the Fourier transform formula,

Fourier transform formula

S 2 f n a n u n 2 f n n 0 a 2 f n

This sum is a special case of the geometric series .

Geometric series

α α 1 n 0 α n 1 1 α
Thus, as long as a 1 , we have our Fourier transform.
S 2 f 1 1 a 2 f

Using Euler's relation, we can express the magnitude and phase of this spectrum.

S 2 f 1 1 a 2 f 2 a 2 2 f 2
S 2 f a 2 f 1 a 2 f

No matter what value of a we choose, the above formulae clearly demonstrate the periodicnature of the spectra of discrete-time signals. [link] shows indeed that the spectrum is a periodic function. We need only consider the spectrumbetween 1 2 and 1 2 to unambiguously define it. When a 0 , we have a lowpass spectrum — the spectrum diminishes as frequency increases from 0 to 1 2 — with increasing a leading to a greater low frequency content; for a 0 , we have a highpass spectrum ( [link] ).

The spectrum of the exponential signal( a 0.5 ) is shown over the frequency range -2 2 , clearly demonstrating the periodicity of all discrete-time spectra. The angle has units of degrees.
The spectra of several exponential signals are shown. What is the apparent relationship between the spectra for a 0.5 and a -0.5 ?

Analogous to the analog pulse signal, let's find the spectrum of the length- N pulse sequence.

s n 1 0 n N 1 0

The Fourier transform of this sequence has the form of a truncated geometric series.

S 2 f n 0 N 1 2 f n

For the so-called finite geometric series, we know that

Finite geometric series

n n 0 N n 0 1 α n α n 0 1 α N 1 α
for all values of α .

Derive this formula for the finite geometric series sum. The "trick" is to consider the difference between theseries'; sum and the sum of the series multiplied by α .

α n n 0 N n 0 1 α n n n 0 N n 0 1 α n α N n 0 α n 0
which, after manipulation, yields the geometric sum formula.

Applying this result yields ( [link] .)

S 2 f 1 2 f N 1 2 f f N 1 f N f

The ratio of sine functions has the generic form of N x x , which is known as the discrete-time sinc function , dsinc x . Thus, our transform can be concisely expressed as S 2 f f N 1 dsinc f . The discrete-time pulse's spectrum contains many ripples, the number of which increase with N , the pulse's duration.

The spectrum of a length-ten pulse is shown. Can you explain the rather complicated appearance of the phase?

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Source:  OpenStax, Ece 454 and ece 554 supplemental reading. OpenStax CNX. Apr 02, 2012 Download for free at http://cnx.org/content/col11416/1.1
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