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9.5 Equations of motion  (Page 2/3)

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A racing car is travelling north. It accelerates uniformly covering a distance of 725 m in 10 s. If it has an initial velocity of 10 m · s - 1 , find its acceleration.

  1. We are given:

    v i = 10 m · s - 1 Δ x = 725 m t = 10 s a = ?

  2. If you struggle to find the correct equation, find the quantity that is not given and then look for an equation that has this quantity in it.

    We can use equation [link]

    Δ x = v i t + 1 2 a t 2
  3. Δ x = v i t + 1 2 a t 2 725 m = ( 10 m · s - 1 × 10 s ) + 1 2 a × ( 10 s ) 2 725 m - 100 m = ( 50 s 2 ) a a = 12 , 5 m · s - 2

  4. The racing car is accelerating at 12,5 m · s - 2 north.

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A motorcycle, travelling east, starts from rest, moves in a straight line with a constant acceleration and covers a distance of 64 m in 4 s. Calculate

  1. its acceleration
  2. its final velocity
  3. at what time the motorcycle had covered half the total distance
  4. what distance the motorcycle had covered in half the total time.

  1. We are given:

    v i = 0 m · s - 1 ( because the object starts from rest. ) Δ x = 64 m t = 4 s a = ? v f = ? t = ? at half the distance Δ x = 32 m . Δ x = ? at half the time t = 2 s .

    All quantities are in SI units.

  2. We can use [link]

    Δ x = v i t + 1 2 a t 2
  3. Δ x = v i t + 1 2 a t 2 64 m = ( 0 m · s - 1 × 4 s ) + 1 2 a × ( 4 s ) 2 64 m = ( 8 s 2 ) a a = 8 m · s - 2 east

  4. We can use [link] - remember we now also know the acceleration of the object.

    v f = v i + a t
  5. v f = v i + a t v f = 0 m · s - 1 + ( 8 m · s - 2 ) ( 4 s ) = 32 m · s - 1 east

  6. We can use [link] :

    Δ x = v i + 1 2 a t 2 32 m = ( 0 m · s - 1 ) t + 1 2 ( 8 m · s - 2 ) ( t ) 2 32 m = 0 + ( 4 m · s - 2 ) t 2 8 s 2 = t 2 t = 2 , 83 s

  7. Half the time is 2 s, thus we have v i , a and t - all in the correct units. We can use [link] to get the distance:

    Δ x = v i t + 1 2 a t 2 = ( 0 ) ( 2 ) + 1 2 ( 8 ) ( 2 ) 2 = 16 m east
    1. The acceleration is 8 m · s - 2 east
    2. The velocity is 32 m · s - 1 east
    3. The time at half the distance is 2,83 s
    4. The distance at half the time is 16 m east
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Equations of motion

  1. A car starts off at 10 m · s - 1 and accelerates at 1 m · s - 2 for 10 s. What is its final velocity?
  2. A train starts from rest, and accelerates at 1 m · s - 2 for 10 s. How far does it move?
  3. A bus is going 30 m · s - 1 and stops in 5 s. What is its stopping distance for this speed?
  4. A racing car going at 20 m · s - 1 stops in a distance of 20 m. What is its acceleration?
  5. A ball has a uniform acceleration of 4 m · s - 1 . Assume the ball starts from rest. Determine the velocity and displacement at the end of 10 s.
  6. A motorcycle has a uniform acceleration of 4 m · s - 1 . Assume the motorcycle has an initial velocity of 20 m · s - 1 . Determine the velocity and displacement at the end of 12 s.
  7. An aeroplane accelerates uniformly such that it goes from rest to 144 km · hr - 1 in 8 s. Calculate the acceleration required and the total distance that it has traveled in this time.

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
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Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
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2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
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you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
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progressive wave
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Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
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Source:  OpenStax, Siyavula textbooks: grade 10 physical science. OpenStax CNX. Aug 29, 2011 Download for free at http://cnx.org/content/col11245/1.3
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