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Acceleration

Acceleration

Acceleration is the rate of change of velocity.

Acceleration (symbol a ) is the rate of change of velocity. It is a measure of how fast the velocity of an object changes in time. If we have a change in velocity ( Δ v ) over a time interval ( Δ t ), then the acceleration ( a ) is defined as:

acceleration ( in m · s - 2 ) = change in velocity ( in m · s - 1 ) change in time ( in s )
a = Δ v Δ t

Since velocity is a vector, acceleration is also a vector. Acceleration does not provide any information about a motion, but only about how the motion changes. It is not possible to tell how fast an object is moving or in which direction from the acceleration.

Like velocity, acceleration can be negative or positive. We see that when the sign of the acceleration and the velocity are the same, the object is speeding up. If both velocity and acceleration are positive, the object is speeding up in a positive direction. If both velocity and acceleration are negative, the object is speeding up in a negative direction. If velocity is positive and acceleration is negative, then the object is slowing down. Similarly, if the velocity is negative and the acceleration is positive the object is slowing down. This is illustrated in the following worked example.

A car accelerates uniformly from an initial velocity of 2 m · s - 1 to a final velocity of 10 m · s 1 in 8 seconds. It then slows down uniformly to a final velocity of 4 m · s - 1 in 6 seconds. Calculate the acceleration of the car during the first 8 seconds and during the last 6 seconds.

  1. Consider the motion of the car in two parts: the first 8 seconds and the last 6 seconds.

    For the first 8 seconds:

    v i = 2 m · s - 1 v f = 10 m · s - 1 t i = 0 s t f = 8 s

    For the last 6 seconds:

    v i = 10 m · s - 1 v f = 4 m · s - 1 t i = 8 s t f = 14 s
  2. For the first 8 seconds:

    a = Δ v Δ t = 10 m · s - 1 - 2 m · s - 1 8 s - 0 s = 1 m · s - 2

    For the next 6 seconds:

    a = Δ v Δ t = 4 m · s - 1 - 10 m · s - 1 14 s - 8 s = - 1 m · s - 2

    During the first 8 seconds the car had a positive acceleration. This means that its velocity increased. The velocity is positive so the car is speeding up. During the next 6 seconds the car had a negative acceleration. This means that its velocity decreased. The velocity is negative so the car is slowing down.

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Acceleration does not tell us about the direction of the motion. Acceleration only tells us how the velocity changes.
Deceleration

Avoid the use of the word deceleration to refer to a negative acceleration. This word usually means slowing down and it is possible for an object to slow down with both a positive and negative acceleration, because the sign of the velocity of the object must also be taken into account to determine whether the body is slowing down or not.

Acceleration

  1. An athlete is accelerating uniformly from an initial velocity of 0 m · s - 1 to a final velocity of 4 m · s - 1 in 2 seconds. Calculate his acceleration. Let the direction that the athlete is running in be the positive direction.
  2. A bus accelerates uniformly from an initial velocity of 15 m · s - 1 to a final velocity of 7 m · s - 1 in 4 seconds. Calculate the acceleration of the bus. Let the direction of motion of the bus be the positive direction.
  3. An aeroplane accelerates uniformly from an initial velocity of 200 m · s - 1 to a velocity of 100 m · s - 1 in 10 seconds. It then accelerates uniformly to a final velocity of 240 m · s - 1 in 20 seconds. Let the direction of motion of the aeroplane be the positive direction.
    1. Calculate the acceleration of the aeroplane during the first 10 seconds of the motion.
    2. Calculate the acceleration of the aeroplane during the next 14 seconds of its motion.

The following video provides a summary of distance, velocity and acceleration. Note that in this video a different convention for writing units is used. You should not use this convention when writing units in physics.

Khan academy video on motion - 1

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
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A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
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what is inorganic
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Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
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A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
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2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
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you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
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progressive wave
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A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
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Source:  OpenStax, Siyavula textbooks: grade 10 physical science. OpenStax CNX. Aug 29, 2011 Download for free at http://cnx.org/content/col11245/1.3
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