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Consider the equation . How many pairs are there that satisfy this equation? Answer: , , , and are all solutions; and there is an infinite number of other solutions . (And don’t forget non-integer solutions, such as !)
Now, consider the equation . How many pairs satisfy this equation? Once again, an infinite number. Most equations that relate two variables have an infinite number of solutions.
To consider these two equations “simultaneously” is to ask the question: what pairs make both equations true ? To express the same question in terms of functions: what values can you hand the functions and that will make these two functions produce the same answer ?
At first glance, it is not obvious how to approach such a question-- it is not even obvious how many answers there will be.
One way to answer such a question is by graphing. Remember, the graph of is the set of all points that satisfy that relationship; and the graph of is the set of all points that satisfy that relationship. So the intersection(s) of these two graphs is the set of all points that satisfy both relationships .
How can we graph these two? The second one is easy: it is a line, already in format. The -intercept is and the slope is 1. We can graph the first equation by plotting points; or, if you happen to know what the graph of looks like, you can stretch the graph vertically to get , since all the -values will double. Either way, you wind up with something like this:
We can see that there are two points of intersection. One occurs when is barely greater than 0 (say, ), and the other occurs at approximately . There will be no more points of intersection after this, because the line will rise faster than the curve.
From graphing...
,
Graphing has three distinct advantages as a method for solving simultaneous equations.
However, graphing also has two dis advantages.
For instance, if you plug the number 3 into both of these functions, will you get the same answer?
Pretty close! Similarly, , which is quite close to 0.6. But if we want more exact answers, we will need to draw a much more exact graph, which becomes very time-consuming. (Rounded to three decimal places, the actual answers are 0.086 and 2.914.)
For more exact answers, we use analytic methods. Two such methods will be discussed in this chapter: substitution and elimination . A third method will be discussed in the section on Matrices.
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