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A student solved the following problem and found the equilibrium concentrations to be [SO 2 ] = 0.590 M , [O 2 ] = 0.0450 M , and [SO 3 ] = 0.260 M . How could this student check the work without reworking the problem? The problem was: For the following reaction at 600 °C:

2 SO 2 ( g ) + O 2 ( g ) 2 SO 3 ( g ) K c = 4.32

What are the equilibrium concentrations of all species in a mixture that was prepared with [SO 3 ] = 0.500 M , [SO 2 ] = 0 M , and [O 2 ] = 0.350 M ?

Calculate Q based on the calculated concentrations and see if it is equal to K c . Because Q does equal 4.32, the system must be at equilibrium.

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A student solved the following problem and found [N 2 O 4 ] = 0.16 M at equilibrium. How could this student recognize that the answer was wrong without reworking the problem? The problem was: What is the equilibrium concentration of N 2 O 4 in a mixture formed from a sample of NO 2 with a concentration of 0.10 M ?

2 NO 2 ( g ) N 2 O 4 ( g ) K c = 160

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Assume that the change in concentration of N 2 O 4 is small enough to be neglected in the following problem.

(a) Calculate the equilibrium concentration of both species in 1.00 L of a solution prepared from 0.129 mol of N 2 O 4 with chloroform as the solvent.

N 2 O 4 ( g ) 2 NO 2 ( g ) K c = 1.07 × 10 −5 in chloroform

(b) Show that the change is small enough to be neglected.

(a) [NO 2 ] = 1.17 × 10 −3 M
[N 2 O 4 ] = 0.128 M
(b) Percent error = 5.87 × 10 −4 0.129 × 100 % = 0.455 % . The change in concentration of N 2 O 4 is far less than the 5% maximum allowed.

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Assume that the change in concentration of COCl 2 is small enough to be neglected in the following problem.

(a) Calculate the equilibrium concentration of all species in an equilibrium mixture that results from the decomposition of COCl 2 with an initial concentration of 0.3166 M .

COCl 2 ( g ) CO ( g ) + Cl 2 ( g ) K c = 2.2 × 10 −10

(b) Show that the change is small enough to be neglected.

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Assume that the change in pressure of H 2 S is small enough to be neglected in the following problem.

(a) Calculate the equilibrium pressures of all species in an equilibrium mixture that results from the decomposition of H 2 S with an initial pressure of 0.824 atm.

2 H 2 S ( g ) 2 H 2 ( g ) + S 2 ( g ) K P = 2.2 × 10 −6

(b) Show that the change is small enough to be neglected.

(a) [H 2 S] = 0.810 atm
[H 2 ] = 0.014 atm
[S 2 ] = 0.0072 atm
(b) The 2 x is dropped from the equilibrium calculation because 0.014 is negligible when subtracted from 0.824. The percent error associated with ignoring 2 x is 0.014 0.824 × 100 % = 1.7 % , which is less than allowed by the “5% test.” The error is, indeed, negligible.

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What are all concentrations after a mixture that contains [H 2 O] = 1.00 M and [Cl 2 O] = 1.00 M comes to equilibrium at 25 °C?

H 2 O ( g ) + Cl 2 O ( g ) 2 HOCl ( g ) K c = 0.0900

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What are the concentrations of PCl 5 , PCl 3 , and Cl 2 in an equilibrium mixture produced by the decomposition of a sample of pure PCl 5 with [PCl 5 ] = 2.00 M ?

PCl 5 ( g ) PCl 3 ( g ) + Cl 2 ( g ) K c = 0.0211

[PCl 3 ] = 1.80 M ; [PC 3 ] = 0.195 M ; [PCl 3 ] = 0.195 M .

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Calculate the pressures of all species at equilibrium in a mixture of NOCl, NO, and Cl 2 produced when a sample of NOCl with a pressure of 10.0 atm comes to equilibrium according to this reaction:
2NOCl ( g ) 2NO ( g ) + Cl 2 ( g ) K P = 4.0 × 10 −4

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Source:  OpenStax, Ut austin - principles of chemistry. OpenStax CNX. Mar 31, 2016 Download for free at http://legacy.cnx.org/content/col11830/1.13
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