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It is convenient to rearrange this equation and introduce a new variable, called the angular frequency , Letting we can write the equation as
This differential equation has the general solution
which gives the position of the mass at any point in time. The motion of the mass is called simple harmonic motion . The period of this motion (the time it takes to complete one oscillation) is and the frequency is ( [link] ).
Assume an object weighing 2 lb stretches a spring 6 in. Find the equation of motion if the spring is released from the equilibrium position with an upward velocity of 16 ft/sec. What is the period of the motion?
We first need to find the spring constant. We have
We also know that weight W equals the product of mass m and the acceleration due to gravity g . In English units, the acceleration due to gravity is 32 ft/sec 2 .
Thus, the differential equation representing this system is
Multiplying through by 16, we get which can also be written in the form This equation has the general solution
The mass was released from the equilibrium position, so and it had an initial upward velocity of 16 ft/sec, so Applying these initial conditions to solve for and gives
The period of this motion is sec.
A 200-g mass stretches a spring 5 cm. Find the equation of motion of the mass if it is released from rest from a position 10 cm below the equilibrium position. What is the frequency of this motion?
(in meters); frequency is Hz.
Writing the general solution in the form has some advantages. It is easy to see the link between the differential equation and the solution, and the period and frequency of motion are evident. This form of the function tells us very little about the amplitude of the motion, however. In some situations, we may prefer to write the solution in the form
Although the link to the differential equation is not as explicit in this case, the period and frequency of motion are still evident. Furthermore, the amplitude of the motion, A , is obvious in this form of the function. The constant is called a phase shift and has the effect of shifting the graph of the function to the left or right.
To convert the solution to this form, we want to find the values of A and such that
We first apply the trigonometric identity
to get
Thus,
If we square both of these equations and add them together, we get
Thus,
Now, to find go back to the equations for and but this time, divide the first equation by the second equation to get
Then,
We summarize this finding in the following theorem.
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