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The thin lens equations can be used to find d i size 12{d rSub { size 8{i} } } {} from the given information:

1 d o + 1 d i = 1 f .

Rearranging to isolate d i gives

1 d i = 1 f 1 d o . size 12{ { {1} over {d rSub { size 8{i} } } } = { {1} over {f} } - { {1} over {d rSub { size 8{o} } } } } {}

Entering known quantities gives a value for 1 / d i :

1 d i = 1 0 . 500 m 1 0 . 750 m = 0.667 m . size 12{ { {1} over {d rSub { size 8{i} } } } = { {1} over {0 "." "500"" m"} } - { {1} over {0 "." "750"" m"} } = { {0 "." "667"} over {m} } } {}

This must be inverted to find d i size 12{d rSub { size 8{i} } } {} :

d i = m 0.667 = 1 . 50 m .

Note that another way to find d i size 12{d rSub { size 8{i} } } {} is to rearrange the equation:

1 d i = 1 f 1 d o . size 12{ { {1} over {d rSub { size 8{i} } } } = { {1} over {f} } - { {1} over {d rSub { size 8{o} } } } } {}

This yields the equation for the image distance as:

d i = fd o d o f .

Note that there is no inverting here.

The thin lens equations can be used to find the magnification m size 12{m} {} , since both d i size 12{d rSub { size 8{i} } } {} and d o size 12{d rSub { size 8{o} } } {} are known. Entering their values gives

m = d i d o = 1.50 m 0.750 m = 2.00 .

Discussion

Note that the minus sign causes the magnification to be negative when the image is inverted. Ray tracing and the use of the thin lens equations produce consistent results. The thin lens equations give the most precise results, being limited only by the accuracy of the given information. Ray tracing is limited by the accuracy with which you can draw, but it is highly useful both conceptually and visually.

Real images, such as the one considered in the previous example, are formed by converging lenses whenever an object is farther from the lens than its focal length. This is true for movie projectors, cameras, and the eye. We shall refer to these as case 1 images. A case 1 image is formed when d o > f size 12{d rSub { size 8{o} }>f} {} and f size 12{f} {} is positive, as in [link] (a). (A summary of the three cases or types of image formation appears at the end of this section.)

A different type of image is formed when an object, such as a person's face, is held close to a convex lens. The image is upright and larger than the object, as seen in [link] (b), and so the lens is called a magnifier. If you slowly pull the magnifier away from the face, you will see that the magnification steadily increases until the image begins to blur. Pulling the magnifier even farther away produces an inverted image as seen in [link] (a). The distance at which the image blurs, and beyond which it inverts, is the focal length of the lens. To use a convex lens as a magnifier, the object must be closer to the converging lens than its focal length. This is called a case 2 image. A case 2 image is formed when d o < f and f is positive.

Figure a shows a lens forming an inverted image of a person’s face when it is held far away from his face. Figure b shows a magnified image of the person’s eye when viewed through a magnifying glass when the lens is placed close to the eye of the person.
(a) When a converging lens is held farther away from the face than the lens’s focal length, an inverted image is formed. This is a case 1 image. Note that the image is in focus but the face is not, because the image is much closer to the camera taking this photograph than the face. (credit: DaMongMan, Flickr) (b) A magnified image of a face is produced by placing it closer to the converging lens than its focal length. This is a case 2 image. (credit: Casey Fleser, Flickr)

[link] uses ray tracing to show how an image is formed when an object is held closer to a converging lens than its focal length. Rays coming from a common point on the object continue to diverge after passing through the lens, but all appear to originate from a point at the location of the image. The image is on the same side of the lens as the object and is farther away from the lens than the object. This image, like all case 2 images, cannot be projected and, hence, is called a virtual image    . Light rays only appear to originate at a virtual image; they do not actually pass through that location in space. A screen placed at the location of a virtual image will receive only diffuse light from the object, not focused rays from the lens. Additionally, a screen placed on the opposite side of the lens will receive rays that are still diverging, and so no image will be projected on it. We can see the magnified image with our eyes, because the lens of the eye converges the rays into a real image projected on our retina. Finally, we note that a virtual image is upright and larger than the object, meaning that the magnification is positive and greater than 1.

Practice Key Terms 8

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Source:  OpenStax, Physics subject knowledge enhancement course (ske). OpenStax CNX. Jan 09, 2015 Download for free at http://legacy.cnx.org/content/col11505/1.10
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