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Some common solubility products are listed in [link] according to their K sp values, whereas a more extensive compilation of products appears in Appendix J . Each of these equilibrium constants is much smaller than 1 because the compounds listed are only slightly soluble. A small K sp represents a system in which the equilibrium lies to the left, so that relatively few hydrated ions would be present in a saturated solution.
Common Solubility Products by Decreasing Equilibrium Constants | |
---|---|
Substance | K sp at 25 °C |
CuCl | 1.2 10 –6 |
CuBr | 6.27 10 –9 |
AgI | 1.5 10 –16 |
PbS | 7 10 –29 |
Al(OH) 3 | 2 10 –32 |
Fe(OH) 3 | 4 10 –38 |
(a) AgI, silver iodide, a solid with antiseptic properties
(b) CaCO 3 , calcium carbonate, the active ingredient in many over-the-counter chewable antacids
(c) Mg(OH) 2 , magnesium hydroxide, the active ingredient in Milk of Magnesia
(d) Mg(NH 4 )PO 4 , magnesium ammonium phosphate, an essentially insoluble substance used in tests for magnesium
(e) Ca 5 (PO 4 ) 3 OH, the mineral apatite, a source of phosphate for fertilizers
(Hint: When determining how to break (d) and (e) up into ions, refer to the list of polyatomic ions in the section on chemical nomenclature.)
(b)
(c)
(d)
(e)
(a) BaSO 4
(b) Ag 2 SO 4
(c) Al(OH) 3
(d) Pb(OH)Cl
(a) (b) (c) (d)
Now we will extend the discussion of K sp and show how the solubility product constant is determined from the solubility of its ions, as well as how K sp can be used to determine the molar solubility of a substance.
Recall that the definition of solubility is the maximum possible concentration of a solute in a solution at a given temperature and pressure. We can determine the solubility product of a slightly soluble solid from that measure of its solubility at a given temperature and pressure, provided that the only significant reaction that occurs when the solid dissolves is its dissociation into solvated ions, that is, the only equilibrium involved is:
In this case, we calculate the solubility product by taking the solid’s solubility expressed in units of moles per liter (mol/L), known as its molar solubility .
The concentration of Ca 2+ in a saturated solution of CaF 2 is 2.15 10 –4 M ; therefore, that of F – is 4.30 10 –4 M , that is, twice the concentration of Ca 2+ . What is the solubility product of fluorite?
A saturated solution is a solution at equilibrium with the solid. Thus:
As with other equilibrium constants, we do not include units with K sp .
8.99 10 –12
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