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We actually still have some options open to us. One of thenicest, at least in terms of getting some insight,is call a crank diagram . Note that this equation is a complex equation, which requires us to take a the ratio of two complexnumbers; and .
Let's plot these two quantities on the complex plane, starting at (the load end of the line). We can represent , the reflection coefficient, by its magnitude and its phase, and . For the numerator we plot a 1, and then add the complex vector which has a length and sits at an angle with respect to the real axis . The denominator is just the same thing, except the vector points in the opposite direction . The top vector is proportional to and the bottom vector is proportional to . Of course, for we are at the load so and . As we move down the line, the two" " vectors rotate around at a rate of . As they rotate, one vector gets longer and the other gets shorter, and then the oppositeoccurs. In any event, to get we have to divide the first vector by the second. In general, this is not easy to do, but there are some places where it is not too bad. One of these is when . At this point, the voltage vector has rotated around so that itis just lying on the real axis. Obviously its length is now . By the same token, the current vector is also lying on the real axis, and has a length . Dividing one by the other, and multiplying by gives us at this point.
Now let's find the magnitude of . To do this we need to square the real and imaginary parts, add them, and then take the square root.
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