<< Chapter < Page Chapter >> Page >

Next we develop a definition of the length of a parameterized curve from a purely mathematical or geometric point of view.Happily, it will turn out to coincide with the physically intuitive definition discussed above.

Let C be a piecewise smooth curve joining the points z 1 and z 2 , and let φ : [ a , b ] C be a parameterization of C . Let P = { a = t 0 < t 1 < ... < t n = b } be a partition of the interval [ a , b ] . For each 0 j n write z j = φ ( t j ) , and think about the polygonal trajectory joining these points { z j } in order. The length L P φ of this polygonal trajectory is given by the formula

L P φ = j = 1 n | z j - z j - 1 | ,

and this length is evidently an approximation to the length of the curve C . Indeed, since the straight line joining two points is the shortest curve joining those points, these polygonal trajectories all should have a length smaller than or equal to the length of the curve.These remarks motivate the following definition.

Let φ : [ a , b ] C be a parameterization of a piecewise smooth curve C C . By the length L φ of C , relative to the parameterization φ , we mean the number L φ = sup P L P φ , where the supremum is taken over all partitions P of [ a , b ] .

Of course, the supremum in the definition above could well equal infinity in some cases.Though it is possible for a curve to have an infinite length, the ones we will study here will have finite lengths.This is another subtlety of this subject. After all, every smooth curve is a compact subset of R 2 , since it is the continuous image of a closed and bounded interval, and we think of compact sets as being “finite” in various ways.However, this finiteness does not necessarily extend to the length of a curve.

Let φ : [ a , b ] R 2 be a parameterization of a piecewise smooth curve C , and let P and Q be two partitions of [ a , b ] .

  1. If P is finer than Q , i.e., Q P , show that L Q φ L P φ .
  2. If φ ( t ) = u ( t ) + i v ( t ) , express L P φ in terms of the numbers u ( t j ) and v ( t j ) .

Of course, we again face the annoying possibility that the definition of length of a curve will depend on the parameterization we are using.However, the next theorem, taken together with [link] , will show that this is not the case.

If C is a piecewise smooth curve parameterized by φ : [ a , b ] C , then

L φ = a b | φ ' ( t ) | d t ,

specifically meaning that one of these quantities is infinite if and only if the other one is infinite.

We prove this theorem for the case when C is a smooth curve, leaving the general argument for a piecewise smooth curve to the exercises.We also only treat here the case when L φ is finite, also leaving the argument for the infinite case to the exercises.Hence, assume that φ = u + i v is a smooth function on [ a , b ] and that L φ < .

Let ϵ > 0 be given. Choose a partition P = { t 0 < t 1 < ... < t n } of [ a , b ] for which

L φ - L P φ = L φ - j = 1 n | φ ( t j ) - φ ( t j - 1 ) | < ϵ .

Because φ is continuous, we may assume by making a finer partition if necessary that the t j 's are such that | φ ( t 1 ) - φ ( t 0 ) | < ϵ and | φ ( t n ) - φ ( t n - 1 ) | < ϵ . This means that

L φ - j = 2 n - 1 | φ ( t j ) - φ ( t j - 1 ) | < 3 ϵ .

The point of this step (trick) is that we know that φ ' is continuous on the open interval ( a , b ) , but we will use that it is uniformly continuous on the compact set [ t 1 , t n - 1 ] . Of course that means that | φ ' | is integrable on that closed interval, and in fact one of the things we need to prove is that | φ ' | is improperly-integrable on the open interval ( a , b ) .

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, Analysis of functions of a single variable. OpenStax CNX. Dec 11, 2010 Download for free at http://cnx.org/content/col11249/1.1
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Analysis of functions of a single variable' conversation and receive update notifications?

Ask