6.1 Graphing two variable inequalities

Algebra i for the community Page 1 / 1

This module is from Elementary Algebra by Denny Burzynski and Wade Ellis, Jr. In this chapter the student is shown how graphs provide information that is not always evident from the equation alone. The chapter begins by establishing the relationship between the variables in an equation, the number of coordinate axes necessary to construct its graph, and the spatial dimension of both the coordinate system and the graph. Interpretation of graphs is also emphasized throughout the chapter, beginning with the plotting of points. The slope formula is fully developed, progressing from verbal phrases to mathematical expressions. The expressions are then formed into an equation by explicitly stating that a ratio is a comparison of two quantities of the same type (e.g., distance, weight, or money). This approach benefits students who take future courses that use graphs to display information.The student is shown how to graph lines using the intercept method, the table method, and the slope-intercept method, as well as how to distinguish, by inspection, oblique and horizontal/vertical lines. Objectives of this module: be able to locate solutions to linear inequalities in two variables using graphical techniques.

Overview

Location of Solutions
Method of Graphing

Location of solutions

In our study of linear equations in two variables, we observed that all the solutions to the equation, and only the solutions to the equation, were located on the graph of the equation. We now wish to determine the location of the solutions to linear inequalities in two variables. Linear inequalities in two variables are inequalities of the forms:

$\begin{matrix} a x + b y \leq c & a x + b y \geq c \\ a x + b y < c & a x + b y > c \end{matrix}$

Half-planes

A straight line drawn through the plane divides the plane into two half-planes .

Boundary line

The straight line is called the boundary line .

A straight line dividing an xy plane in two half-planes.

Solution to an inequality in two variables

Recall that when working with linear equations in two variables, we observed that ordered pairs that produced true statements when substituted into an equation were called solutions to that equation. We can make a similar statement for inequalities in two variables. We say that an inequality in two variables has a solution when a pair of values has been found such that when these values are substituted into the inequality a true statement results.

The location of solutions in the plane

As with equations, solutions to linear inequalities have particular locations in the plane. All solutions to a linear inequality in two variables are located in one and only in one entire half-plane. For example, consider the inequality

$2 x + 3 y \leq 6$

A straight line in an xy plane passing through two points with coordinates zero, two and three, zero. Equation of this line is two x plus three y equal to six. Points lying in the shaded region below the line are the solutions of inequality two x plus three y less than equal to six.

All the solutions to the inequality $2 x + 3 y \leq 6$ lie in the shaded half-plane.

Point $A (1, - 1)$ is a solution since

$\begin{array}{l} 2 x + 3 y \leq 6 \\ 2 (1) + 3 (- 1) \leq 6 ? \\ 2 - 3 \leq 6 ? \\ - 1 \leq 6. True \end{array}$

Point $B (2, 5)$ is not a solution since

$\begin{array}{l} 2 x + 3 y \leq 6 \\ 2 (2) + 3 (5) \leq 6 ? \\ 4 + 15 \leq 6 ? \\ 19 \leq 6. False \end{array}$

Method of graphing

The method of graphing linear inequalities in two variables is as follows:

Graph the boundary line (consider the inequality as an equation, that is, replace the inequality sign with an equal sign).
1. If the inequality is $\leq$ or $\geq$ , draw the boundary line solid . This means that points on the line are solutions and are part of the graph.
2. If the inequality is $<$ or $>$ , draw the boundary line dotted . This means that points on the line are not solutions and are not part of the graph.
Determine which half-plane to shade by choosing a test point.
1. If, when substituted, the test point yields a true statement, shade the half-plane containing it.
2. If, when substituted, the test point yields a false statement, shade the half-plane on the opposite side of the boundary line.

Sample set a

Graph $3 x - 2 y \geq - 4$ .

1. Graph the boundary line. The inequality is $\geq$ so we’ll draw the line solid . Consider the inequality as an equation.

3 x - 2 y = - 4

$x$	$y$	$(x, y)$
$\begin{array}{r} 0 \\ \frac{- 4}{3} \end{array}$	$\begin{matrix} 2 \\ 0 \end{matrix}$	$\begin{array}{l} (0, 2) \\ (\frac{- 4}{3}, 0) \end{array}$

A graph of a line passing through two points with coordinates zero, two and negative four upon three, zero. Boundary line points on this line are included in solutions of inequality.

2. Choose a test point. The easiest one is $(0, 0)$ . Substitute $(0, 0)$ into the original inequality.

\begin{array}{l} 3 x - 2 y \geq - 4 \\ 3 (0) - 2 (0) \geq - 4 ? \\ 0 - 0 \geq - 4 ? \\ 0 \geq - 4. True \end{array}

Shade the half-plane containing

(0, 0)

A straight line in an xy plane passing through two points with coordinates zero, two and negative four upon three, zero. Points lying in the region to the right of the line are solutions of the inequality and points lying in the region left to the line are not solutions of the inequality. The test point zero, zero belongs to the shaded region.

Graph $x + y - 3 < 0$ .

1. Graph the boundary line: $x + y - 3 = 0$ . The inequality is $<$ so we’ll draw the line dotted .

A graph of a dashed line passing through two points with coordinates zero, three and three, zero. Boundary line points on this line are not included in the solutions of the inequality.

2. Choose a test point, say $(0, 0)$ .

\begin{array}{l} x + y - 3 < 0 \\ 0 + 0 - 3 < 0 ? \\ - 3 < 0. True \end{array}

Shade the half-plane containing

(0, 0)

A dashed straight line in an xy plane passing through two points with coordinates zero, three and three, zero. The region to the left of the line is shaded. The test point zero, zero belongs to the shaded region.

Graph $y \leq 2 x$ .

Graph the boundary line $y = 2 x$ . The inequality is $\leq$ , so we’ll draw the line solid .
Choose a test point, say $(0, 0)$ .
$\begin{array}{l} y \leq 2 x \\ 0 \leq 2 (0) ? \\ 0 \leq 0. True \end{array}$
Shade the half-plane containing $(0, 0)$ . We can’t! $(0, 0)$ is right on the line! Pick another test point, say $(1, 6)$ .
$\begin{array}{l} y \leq 2 x \\ 6 \leq 2 (1) ? \\ 6 \leq 2. False \end{array}$
Shade the half-plane on the opposite side of the boundary line.

Graph $y > 2$ .

1. Graph the boundary line $y = 2$ . The inequality is $>$ so we’ll draw the line dotted .

A graph of a dashed line parallel to x axis and passing through point with coordinates zero, two.

2. We don’t really need a test point. Where is $y > 2 ?$ Above the line $y = 2!$ Any point above the line clearly has a $y -coordinate$ greater than 2.

A dashed straight line in an xy plane parallel to x axis and passing through point with coordinates zero, two. The region above the line is shaded.

Practice set a

Solve the following inequalities by graphing.

$- 3 x + 2 y \leq 4$

An xy-plane with gridlines, labeled negative five and five on the both axes.

A straight line in an xy plane passing through two points with coordinates zero, two and two, five. The region to the right of the line is shaded.

$x - 4 y < 4$

An xy-plane with gridlines, labeled negative five and five on the both axes.

A dashed straight line in an xy plane passing through two points with coordinates zero, negative one and four, zero. The region above the line is shaded.

$3 x + y > 0$

An xy-plane with gridlines, labeled negative five and five on the both axes.

A dashed straight line in an xy plane passing through two points with coordinates zero, zero and one, negative three. The region right to the line is shaded.

$x \geq 1$

An xy-plane with gridlines, labeled negative five and five on the both axes.

A straight line in an xy plane parallel to the y-axis is passing through a point with coordinates one, zero. The region right to the line is shaded.

Exercises

Solve the inequalities by graphing.

$y < x + 1$

An xy-plane with gridlines, labeled negative five and five on the both axes.

A dashed line in an xy plane passing through two points with coordinates zero, one and negative one, zero. The region below the line is shaded.

$x + y \leq 1$

An xy-plane with gridlines, labeled negative five and five on the both axes.

$- x + 2 y + 4 \geq 0$

An xy-plane with gridlines, labeled negative five and five on the both axes.

A line in an xy plane passing through two points with coordinates zero, negative two and four, zero. The region above the line is shaded.

$- x + 5 y - 10 < 0$

An xy-plane with gridlines, labeled negative five and five on the both axes.

$- 3 x + 4 y > - 12$

An xy-plane with gridlines, labeled negative five and five on the both axes.

A dashed line in an xy plane passing through two points with coordinates zero, negative three and four, zero. The region above the line is shaded.

$2 x + 5 y - 15 \geq 0$

An xy-plane with gridlines, labeled negative five and five on the both axes.

$y \leq 4$

An xy-plane with gridlines, labeled negative five and five on the both axes.

A line parallel to x-axis in an xy plane.The line crosses the y-axis at y equals four. The region below the line is shaded.

$x \geq 2$

An xy-plane with gridlines, labeled negative five and five on the both axes.

$x \leq 0$

An xy-plane with gridlines, labeled negative five and five on the both axes.

An xy-coordinate plane with the region to the left of the y-axis is shaded.

$x - y < 0$

An xy-plane with gridlines, labeled negative five and five on the both axes.

$x + 3 y \geq 0$

An xy-plane with gridlines, labeled negative five and five on the both axes.

A line in an xy plane passing through two points with coordinates negative three, one and three, negative one. The region above the line is shaded.

$- 2 x + 4 y > 0$

An xy-plane with gridlines, labeled negative five and five on the both axes.

Exercises for review

( [link] ) Graph the inequality $- 3 x + 5 \geq - 1$ .

A number line with arrows on each end, labeled from negative three to three, in increments of one. There is an open circle at two. A dark line is orginating from this circle, and heading towards the left of two.

( [link] ) Supply the missing word. The geometric representation (picture) of the solutions to an equation is called the of the equation.

( [link] ) Supply the denominator: $m = \frac{y_{2} - y_{1}}{?}$ .

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

( [link] ) Graph the equation $y = - 3 x + 2$ .

An xy-plane with gridlines, labeled negative five and five on the both axes.

( [link] ) Write the equation of the line that has slope 4 and passes through the point $(- 1, 2)$ .

$y = 4 x + 6$

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Source: OpenStax, Algebra i for the community college. OpenStax CNX. Dec 19, 2014 Download for free at http://legacy.cnx.org/content/col11598/1.3

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