Discussion of Discrete-time Fourier Transforms. Topics include comparison with analog transforms and discussion of Parseval's theorem.
The Fourier transform of the discrete-time signal
is defined to be
Frequency here has no units. As should be expected, thisdefinition is linear, with the transform of a sum of signals
equaling the sum of their transforms. Real-valued signals haveconjugate-symmetric spectra:
.
A special property of the discrete-time Fourier transform isthat it is periodic with period one:
.
Derive this property from the definition of the DTFT.
Because of this periodicity, we need only plot the spectrum overone period to understand completely the spectrum's structure;
typically, we plot the spectrum over the frequency range
.
When the signal is real-valued, we can further simplify ourplotting chores by showing the spectrum only over
;
the spectrum at negative frequencies can be derived frompositive-frequency spectral values.
When we obtain the discrete-time signal via sampling an analog
signal, the
Nyquist frequency corresponds to the
discrete-time frequency
. To show this, note that a sinusoid having a
frequency equal to the Nyquist frequency
has a sampled waveform that equals
The exponential in the DTFT at frequency
equals
, meaning that discrete-time frequency equals analog
frequency multiplied by the sampling interval
and
represent discrete-time and analog frequency
variables, respectively. The
aliasing figure provides
another way of deriving this result. As the duration of eachpulse in the periodic sampling signal
narrows, the amplitudes of the signal's spectral
repetitions, which are governed by the
Fourier series coefficients of
, become increasingly equal. Examination of the
periodic pulse
signal reveals that as
decreases, the value of
,
the largest Fourier coefficient, decreases to zero:
.
Thus, to maintain a mathematically viable Sampling Theorem, theamplitude
must increase as
, becoming infinitely large as the pulse duration
decreases. Practical systems use a small value of
, say
and use amplifiers to rescale the signal. Thus, the sampledsignal's spectrum becomes periodic with period
.
Thus, the Nyquist frequency
corresponds to the frequency
.
Let's compute the discrete-time Fourier transform of the
exponentially decaying sequence
,
where
is the unit-step sequence. Simply plugging the signal'sexpression into the Fourier transform formula,
This sum is a special case of the
geometric
series .
Thus, as long as
,
we have our Fourier transform.
Using Euler's relation, we can express the magnitude and phase
of this spectrum.
No matter what value of
we
choose, the above formulae clearly demonstrate the periodicnature of the spectra of discrete-time signals.
[link] shows indeed that the spectrum
is a periodic function. We need only consider the spectrumbetween
and
to unambiguously define it. When
,
we have a lowpass spectrum—the spectrum diminishes asfrequency increases from 0 to
—with increasing
leading to a greater low frequency
content; for
,
we have a highpass spectrum(
[link] ).
Derive this formula for the finite geometric series sum.
The "trick" is to consider the difference between theseries' sum and the sum of the series multiplied by
.
which, after manipulation, yields the geometric sum formula.
The ratio of sine functions has the generic form of
,
which is known as the
discrete-time sinc function
.
Thus, our transform can be concisely expressed as
. The discrete-time pulse's spectrum contains many
ripples, the number of which increase with
, the pulse's duration.
The inverse discrete-time Fourier transform is easily derived
from the following relationship:
Therefore, we find that
The Fourier transform pairs in discrete-time are
The properties of the discrete-time Fourier transform mirror
those of the analog Fourier transform. The
DTFT properties table shows similarities and differences. One important common
property is Parseval's Theorem.
To show this important property, we simply substitute theFourier transform expression into the frequency-domain
expression for power.
Using the
orthogonality
relation , the integral equals
,
where
is the
unit sample . Thus, the double sum collapses
into a single sum because nonzero values occur only when
,
giving Parseval's Theorem as a result. We term
the energy in the discrete-time signal
in spite of the fact that discrete-time signals don't consume(or produce for that matter) energy. This terminology is a
carry-over from the analog world.
Suppose we obtained our discrete-time signal from values ofthe product
,
where the duration of the component pulses in
is
. How is
the discrete-time signal energy related to the total energycontained in
?
Assume the signal is bandlimited and that the sampling ratewas chosen appropriate to the Sampling Theorem's conditions.
If the sampling frequency exceeds the Nyquist frequency, thespectrum of the samples equals the analog spectrum, but overthe normalized analog frequency
. Thus, the energy in the sampled signal equals
the original signal's energy multiplied by
.
A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
Adjei
please, I'm a physics student and I need help in physics
Adjanou
chemistry could also be understood like the sexual attraction/repulsion of the male and female elements. the reaction varies depending on the energy differences of each given gender. + masculine -female.
Pedro
A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
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you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?