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In 2012, 1,664,479 students took the SAT exam. The distribution of scores in the verbal section of the SAT had a mean µ = 496 and a standard deviation σ = 114. Let X = a SAT exam verbal section score in 2012. Then X ~ N (496, 114).

Find the z -scores for x 1 = 325 and x 2 = 366.21. Interpret each z -score. What can you say about x 1 = 325 and x 2 = 366.21?

The z -score for x 1 = 325 is z 1 = –1.14.

The z -score for x 2 = 366.21 is z 2 = –1.14.

Student 2 scored closer to the mean than Student 1 and, since they both had negative z -scores, Student 2 had the better score.

Suppose x has a normal distribution with mean 50 and standard deviation 6.

  • About 68% of the x values lie between –1 σ = (–1)(6) = –6 and 1 σ = (1)(6) = 6 of the mean 50. The values 50 – 6 = 44 and 50 + 6 = 56 are within one standard deviation of the mean 50. The z -scores are –1 and +1 for 44 and 56, respectively.
  • About 95% of the x values lie between –2 σ = (–2)(6) = –12 and 2 σ = (2)(6) = 12. The values 50 – 12 = 38 and 50 + 12 = 62 are within two standard deviations of the mean 50. The z -scores are –2 and +2 for 38 and 62, respectively.
  • About 99.7% of the x values lie between –3 σ = (–3)(6) = –18 and 3 σ = (3)(6) = 18 of the mean 50. The values 50 – 18 = 32 and 50 + 18 = 68 are within three standard deviations of the mean 50. The z -scores are –3 and +3 for 32 and 68, respectively.

Try it

Suppose X has a normal distribution with mean 25 and standard deviation five. Between what values of x do 68% of the values lie?

between 20 and 30.

From 1984 to 1985, the mean height of 15 to 18-year-old males from Chile was 172.36 cm, and the standard deviation was 6.34 cm. Let Y = the height of 15 to 18-year-old males in 1984 to 1985. Then Y ~ N (172.36, 6.34).

  1. About 68% of the y values lie between what two values? These values are ________________. The z -scores are ________________, respectively.
  2. About 95% of the y values lie between what two values? These values are ________________. The z -scores are ________________ respectively.
  3. About 99.7% of the y values lie between what two values? These values are ________________. The z -scores are ________________, respectively.

  1. About 68% of the values lie between 166.02 and 178.7. The z -scores are –1 and 1.
  2. About 95% of the values lie between 159.68 and 185.04. The z -scores are –2 and 2.
  3. About 99.7% of the values lie between 153.34 and 191.38. The z -scores are –3 and 3.

Try it

The scores on a college entrance exam have an approximate normal distribution with mean, µ = 52 points and a standard deviation, σ = 11 points.

  1. About 68% of the y values lie between what two values? These values are ________________. The z -scores are ________________, respectively.
  2. About 95% of the y values lie between what two values? These values are ________________. The z -scores are ________________, respectively.
  3. About 99.7% of the y values lie between what two values? These values are ________________. The z -scores are ________________, respectively.
  1. About 68% of the values lie between the values 41 and 63. The z -scores are –1 and 1, respectively.
  2. About 95% of the values lie between the values 30 and 74. The z -scores are –2 and 2, respectively.
  3. About 99.7% of the values lie between the values 19 and 85. The z -scores are –3 and 3, respectively.

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Source:  OpenStax, Statistics i - math1020 - red river college - version 2015 revision a - draft 2015-10-24. OpenStax CNX. Oct 24, 2015 Download for free at http://legacy.cnx.org/content/col11891/1.8
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