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For the following exercises, find the limit of the function.

lim ( x , y ) ( 1 , 2 ) x

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lim ( x , y ) ( 1 , 2 ) 5 x 2 y x 2 + y 2

2.0

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Show that the limit lim ( x , y ) ( 0 , 0 ) 5 x 2 y x 2 + y 2 exists and is the same along the paths: y -axis and x -axis, and along y = x .

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For the following exercises, evaluate the limits at the indicated values of x and y . If the limit does not exist, state this and explain why the limit does not exist.

lim ( x , y ) ( 0 , 0 ) 4 x 2 + 10 y 2 + 4 4 x 2 10 y 2 + 6

2 3

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lim ( x , y ) ( 11 , 13 ) 1 x y

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lim ( x , y ) ( 0 , 1 ) y 2 sin x x

1

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lim ( x , y ) ( 0 , 0 ) sin ( x 8 + y 7 x y + 10 )

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lim ( x , y ) ( π / 4 , 1 ) y tan x y + 1

1 2

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lim ( x , y ) ( 0 , π / 4 ) sec x + 2 3 x tan y

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lim ( x , y ) ( 2 , 5 ) ( 1 x 5 y )

1 2

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lim ( x , y ) ( 4 , 4 ) x ln y

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lim ( x , y ) ( 4 , 4 ) e x 2 y 2

e −32

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lim ( x , y ) ( 0 , 0 ) 9 x 2 y 2

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lim ( x , y ) ( 1 , 2 ) ( x 2 y 3 x 3 y 2 + 3 x + 2 y )

11.0

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lim ( x , y ) ( π , π ) x sin ( x + y 4 )

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lim ( x , y ) ( 0 , 0 ) x y + 1 x 2 + y 2 + 1

1.0

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lim ( x , y ) ( 0 , 0 ) x 2 + y 2 x 2 + y 2 + 1 1

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lim ( x , y ) ( 0 , 0 ) ln ( x 2 + y 2 )

The limit does not exist because when x and y both approach zero, the function approaches ln 0 , which is undefined (approaches negative infinity).

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For the following exercises, complete the statement.

A point ( x 0 , y 0 ) in a plane region R is an interior point of R if _________________.

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A point ( x 0 , y 0 ) in a plane region R is called a boundary point of R if ___________.

every open disk centered at ( x 0 , y 0 ) contains points inside R and outside R

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For the following exercises, use algebraic techniques to evaluate the limit.

lim ( x , y ) ( 2 , 1 ) x y 1 x y 1

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lim ( x , y ) ( 0 , 0 ) x 4 4 y 4 x 2 + 2 y 2

0.0

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lim ( x , y ) ( 0 , 0 ) x 3 y 3 x y

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lim ( x , y ) ( 0 , 0 ) x 2 x y x y

0.00

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For the following exercises, evaluate the limits of the functions of three variables.

lim ( x , y , z ) ( 1 , 2 , 3 ) x z 2 y 2 z x y z 1

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lim ( x , y , z ) ( 0 , 0 , 0 ) x 2 y 2 z 2 x 2 + y 2 z 2

The limit does not exist.

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For the following exercises, evaluate the limit of the function by determining the value the function approaches along the indicated paths. If the limit does not exist, explain why not.

lim ( x , y ) ( 0 , 0 ) x y + y 3 x 2 + y 2

  1. Along the x -axis ( y = 0 )
  2. Along the y -axis ( x = 0 )
  3. Along the path y = 2 x
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Evaluate lim ( x , y ) ( 0 , 0 ) x y + y 3 x 2 + y 2 using the results of previous problem.

The limit does not exist. The function approaches two different values along different paths.

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lim ( x , y ) ( 0 , 0 ) x 2 y x 4 + y 2

  1. Along the x -axis ( y = 0 )
  2. Along the y -axis ( x = 0 )
  3. Along the path y = x 2
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Evaluate lim ( x , y ) ( 0 , 0 ) x 2 y x 4 + y 2 using the results of previous problem.

The limit does not exist because the function approaches two different values along the paths.

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Discuss the continuity of the following functions. Find the largest region in the x y -plane in which the following functions are continuous.

f ( x , y ) = sin ( x y )

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f ( x , y ) = ln ( x + y )

The function f is continuous in the region y > x .

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f ( x , y ) = 1 x y

The function f is continuous at all points in the x y -plane except at ( 0 , 0 ) .

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For the following exercises, determine the region in which the function is continuous. Explain your answer.

f ( x , y ) = x 2 y x 2 + y 2

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f ( x , y ) = { x 2 y x 2 + y 2 if ( x , y ) ( 0 , 0 ) 0 if ( x , y ) = ( 0 , 0 ) }

( Hint : Show that the function approaches different values along two different paths.)

The function is continuous at ( 0 , 0 ) since the limit of the function at ( 0 , 0 ) is 0 , the same value of f ( 0 , 0 ) .

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f ( x , y ) = sin ( x 2 + y 2 ) x 2 + y 2

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Determine whether g ( x , y ) = x 2 y 2 x 2 + y 2 is continuous at ( 0 , 0 ) .

The function is discontinuous at ( 0 , 0 ) . The limit at ( 0 , 0 ) fails to exist and g ( 0 , 0 ) does not exist.

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Create a plot using graphing software to determine where the limit does not exist. Determine the region of the coordinate plane in which f ( x , y ) = 1 x 2 y is continuous.

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Determine the region of the x y -plane in which the composite function g ( x , y ) = arctan ( x y 2 x + y ) is continuous. Use technology to support your conclusion.

Since the function arctan x is continuous over ( , ) , g ( x , y ) = arctan ( x y 2 x + y ) is continuous where z = x y 2 x + y is continuous. The inner function z is continuous on all points of the x y -plane except where y = x . Thus, g ( x , y ) = arctan ( x y 2 x + y ) is continuous on all points of the coordinate plane except at points at which y = x .

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Determine the region of the x y -plane in which f ( x , y ) = ln ( x 2 + y 2 1 ) is continuous. Use technology to support your conclusion. ( Hint : Choose the range of values for x and y carefully!)

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At what points in space is g ( x , y , z ) = x 2 + y 2 2 z 2 continuous?

All points P ( x , y , z ) in space

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At what points in space is g ( x , y , z ) = 1 x 2 + z 2 1 continuous?

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Show that lim ( x , y ) ( 0 , 0 ) 1 x 2 + y 2 does not exist at ( 0 , 0 ) by plotting the graph of the function.

The graph increases without bound as x and y both approach zero.
On xyz space, there is a shape drawn that decreases to 0 as x and y increase or decrease but that increases greatly closer to the origin. It increases to such an extent that the graph is cut off above z = 10, which coincides with a circle of radius 0.6 around (0, 0, 10).

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[T] Evaluate lim ( x , y ) ( 0 , 0 ) x y 2 x 2 + y 4 by plotting the function using a CAS. Determine analytically the limit along the path x = y 2 .

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[T]

  1. Use a CAS to draw a contour map of z = 9 x 2 y 2 .
  2. What is the name of the geometric shape of the level curves?
  3. Give the general equation of the level curves.
  4. What is the maximum value of z ?
  5. What is the domain of the function?
  6. What is the range of the function?

a.
A series of five concentric circles, with radii 3, 2.75, 2.5, 2.2, and 1.75. The areas between the circles are colored, with the darkest color between the circles of radii 3 and 2.75.
b. The level curves are circles centered at ( 0 , 0 ) with radius 9 c . c. x 2 + y 2 = 9 c d. z = 3 e. { ( x , y ) 2 | x 2 + y 2 9 } f. { z | 0 z 3 }

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True or False : If we evaluate lim ( x , y ) ( 0 , 0 ) f ( x ) along several paths and each time the limit is 1 , we can conclude that lim ( x , y ) ( 0 , 0 ) f ( x ) = 1 .

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Use polar coordinates to find lim ( x , y ) ( 0 , 0 ) sin x 2 + y 2 x 2 + y 2 . You can also find the limit using L’Hôpital’s rule.

1.0

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Use polar coordinates to find lim ( x , y ) ( 0 , 0 ) cos ( x 2 + y 2 ) .

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Discuss the continuity of f ( g ( x , y ) ) where f ( t ) = 1 / t and g ( x , y ) = 2 x 5 y .

f ( g ( x , y ) ) is continuous at all points ( x , y ) that are not on the line 2 x 5 y = 0 .

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Given f ( x , y ) = x 2 4 y , find lim h 0 f ( x + h , y ) f ( x , y ) h .

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Given f ( x , y ) = x 2 4 y , find lim h 0 f ( 1 + h , y ) f ( 1 , y ) h .

2.0

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Practice Key Terms 8

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Source:  OpenStax, Calculus volume 3. OpenStax CNX. Feb 05, 2016 Download for free at http://legacy.cnx.org/content/col11966/1.2
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