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  • Calculate the limit of a function of two variables.
  • Learn how a function of two variables can approach different values at a boundary point, depending on the path of approach.
  • State the conditions for continuity of a function of two variables.
  • Verify the continuity of a function of two variables at a point.
  • Calculate the limit of a function of three or more variables and verify the continuity of the function at a point.

We have now examined functions of more than one variable and seen how to graph them. In this section, we see how to take the limit of a function of more than one variable, and what it means for a function of more than one variable to be continuous at a point in its domain. It turns out these concepts have aspects that just don’t occur with functions of one variable.

Limit of a function of two variables

Recall from Section 2.2 the definition of a limit of a function of one variable:

Let f ( x ) be defined for all x a in an open interval containing a . Let L be a real number. Then

lim x a f ( x ) = L

if for every ε > 0 , there exists a δ > 0 , such that if 0 < | x a | < δ for all x in the domain of f , then

| f ( x ) L | > ε .

Before we can adapt this definition to define a limit of a function of two variables, we first need to see how to extend the idea of an open interval in one variable to an open interval in two variables.

Definition

Consider a point ( a , b ) 2 . A δ disk    centered at point ( a , b ) is defined to be an open disk of radius δ centered at point ( a , b ) —that is,

{ ( x , y ) 2 | ( x a ) 2 + ( y b ) 2 < δ 2 }

as shown in the following graph.

On the xy plane, the point (2, 1) is shown, which is the center of a circle of radius δ.
A δ disk centered around the point ( 2 , 1 ) .

The idea of a δ disk appears in the definition of the limit of a function of two variables. If δ is small, then all the points ( x , y ) in the δ disk are close to ( a , b ) . This is completely analogous to x being close to a in the definition of a limit of a function of one variable. In one dimension, we express this restriction as

a δ < x < a + δ .

In more than one dimension, we use a δ disk.

Definition

Let f be a function of two variables, x and y . The limit of f ( x , y ) as ( x , y ) approaches ( a , b ) is L , written

lim ( x , y ) ( a , b ) f ( x , y ) = L

if for each ε > 0 there exists a small enough δ > 0 such that for all points ( x , y ) in a δ disk around ( a , b ) , except possibly for ( a , b ) itself, the value of f ( x , y ) is no more than ε away from L ( [link] ). Using symbols, we write the following: For any ε > 0 , there exists a number δ > 0 such that

| f ( x , y ) L | < ε whenever 0 < ( x a ) 2 + ( y b ) 2 < δ .
In xyz space, a function is drawn with point L. This point L is the center of a circle of radius ॉ, with points L ± ॉ marked. On the xy plane, there is a point (a, b) drawn with a circle of radius δ around it. This is denoted the δ-disk. There are dashed lines up from the δ-disk to make a disk on the function, which is called the image of delta disk. Then there are dashed lines from this disk to the circle around the point L, which is called the ॉ-neighborhood of L.
The limit of a function involving two variables requires that f ( x , y ) be within ε of L whenever ( x , y ) is within δ of ( a , b ) . The smaller the value of ε , the smaller the value of δ .

Proving that a limit exists using the definition of a limit of a function of two variables can be challenging. Instead, we use the following theorem, which gives us shortcuts to finding limits. The formulas in this theorem are an extension of the formulas in the limit laws theorem in The Limit Laws .

Limit laws for functions of two variables

Let f ( x , y ) and g ( x , y ) be defined for all ( x , y ) ( a , b ) in a neighborhood around ( a , b ) , and assume the neighborhood is contained completely inside the domain of f . Assume that L and M are real numbers such that lim ( x , y ) ( a , b ) f ( x , y ) = L and lim ( x , y ) ( a , b ) g ( x , y ) = M , and let c be a constant. Then each of the following statements holds:

Constant Law:

lim ( x , y ) ( a , b ) c = c

Identity Laws:

lim ( x , y ) ( a , b ) x = a
lim ( x , y ) ( a , b ) y = b

Sum Law:

lim ( x , y ) ( a , b ) ( f ( x , y ) + g ( x , y ) ) = L + M

Difference Law:

lim ( x , y ) ( a , b ) ( f ( x , y ) g ( x , y ) ) = L M

Constant Multiple Law:

lim ( x , y ) ( a , b ) ( c f ( x , y ) ) = c L

Product Law:

lim ( x , y ) ( a , b ) ( f ( x , y ) g ( x , y ) ) = L M

Quotient Law:

lim ( x , y ) ( a , b ) f ( x , y ) g ( x , y ) = L M for M 0

Power Law:

lim ( x , y ) ( a , b ) ( f ( x , y ) ) n = L n

for any positive integer n .

Root Law:

lim ( x , y ) ( a , b ) f ( x , y ) n = L n

for all L if n is odd and positive, and for L 0 if n is even and positive.

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
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A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
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what is inorganic
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Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
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A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
Krampah Reply
2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
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you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
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"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
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A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
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Source:  OpenStax, Calculus volume 3. OpenStax CNX. Feb 05, 2016 Download for free at http://legacy.cnx.org/content/col11966/1.2
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