Suppose that 10,000 U.S. licensed drivers are randomly selected.
How many would you expect to be male?
Using the table or tree diagram from the previous exercise, construct a contingency table of gender versus age group.
Using the contingency table, find the probability that out of the age 20 - 64 group, a randomly selected driver is female.
5140
0.49
Approximately 86.5% of Americans commute to work by car, truck or van. Out of that group, 84.6% drive alone and 15.4% drive in a carpool. Approximately 3.9% walk to work and approximately 5.3% take public transportation. (
Source: Bureau of the Census, U.S. Dept. of Commerce. Disregard rounding approximations. )
Construct a table or a tree diagram of the situation. Include a branch for all other modes of transportation to work.
Assuming that the walkers walk alone, what percent of all commuters travel alone to work?
Suppose that 1000 workers are randomly selected. How many would you expect to travel alone to work?
Suppose that 1000 workers are randomly selected. How many would you expect to drive in a carpool?
Explain what is wrong with the following statements. Use complete sentences.
If there’s a 60% chance of rain on Saturday and a 70% chance of rain on Sunday, then there’s a 130% chance of rain over the weekend.
The probability that a baseball player hits a home run is greater than the probability that he gets a successful hit.
Try these multiple choice questions.
The next two questions refer to the following probability tree diagram which shows tossing an unfair coin
FOLLOWED BY drawing one bead from a cup containing 3 red (
), 4 yellow (
) and 5 blue (
) beads. For the coin,
and
where
and
.
Find
C
Find
.
A
The next three questions refer to the following table of data obtained from
www.baseball-almanac.com showing hit information for 4 well known baseball players. Suppose that one hit from the table is randomly selected.
NAME
Single
Double
Triple
Home Run
TOTAL HITS
Babe Ruth
1517
506
136
714
2873
Jackie Robinson
1054
273
54
137
1518
Ty Cobb
3603
174
295
114
4189
Hank Aaron
2294
624
98
755
3771
TOTAL
8471
1577
583
1720
12351
Find
.
B
Find
B
Are
and
independent events?
Yes, because
No, because
No, because
Yes, because
C
Given events G and H: P(G) = 0.43 ; P(H) = 0.26 ; P(H and G) = 0.14
Find P(H or G)
Find the probability of the complement of event (H and G)
Find the probability of the complement of event (H or G)
P(H or G) = P(H) + P(G) − P(H and G) = 0.26 + 0.43 − 0.14 = 0.55
P( NOT (H and G) ) = 1 − P(H and G) = 1 − 0.14 = 0.86
P( NOT (H or G) ) = 1 − P(H or G) = 1 − 0.55 = 0.45
Receive real-time job alerts and never miss the right job again
Source:
OpenStax, Collaborative statistics using spreadsheets. OpenStax CNX. Jan 05, 2016 Download for free at http://legacy.cnx.org/content/col11521/1.23
Google Play and the Google Play logo are trademarks of Google Inc.
Notification Switch
Would you like to follow the 'Collaborative statistics using spreadsheets' conversation and receive update notifications?