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We have seen some techniques that allow us to integrate specific rational functions. For example, we know that
However, we do not yet have a technique that allows us to tackle arbitrary quotients of this type. Thus, it is not immediately obvious how to go about evaluating However, we know from material previously developed that
In fact, by getting a common denominator, we see that
Consequently,
In this section, we examine the method of partial fraction decomposition , which allows us to decompose rational functions into sums of simpler, more easily integrated rational functions. Using this method, we can rewrite an expression such as: as an expression such as
The key to the method of partial fraction decomposition is being able to anticipate the form that the decomposition of a rational function will take. As we shall see, this form is both predictable and highly dependent on the factorization of the denominator of the rational function. It is also extremely important to keep in mind that partial fraction decomposition can be applied to a rational function only if In the case when we must first perform long division to rewrite the quotient in the form where We then do a partial fraction decomposition on The following example, although not requiring partial fraction decomposition, illustrates our approach to integrals of rational functions of the form where
Evaluate
Since we perform long division to obtain
Thus,
Visit this website for a review of long division of polynomials.
To integrate where we must begin by factoring
If can be factored as where each linear factor is distinct, then it is possible to find constants satisfying
The proof that such constants exist is beyond the scope of this course.
In this next example, we see how to use partial fractions to integrate a rational function of this type.
Evaluate
Since we begin by factoring the denominator of We can see that Thus, there are constants and satisfying
We must now find these constants. To do so, we begin by getting a common denominator on the right. Thus,
Now, we set the numerators equal to each other, obtaining
There are two different strategies for finding the coefficients and We refer to these as the method of equating coefficients and the method of strategic substitution .
Rewrite [link] in the form
Equating coefficients produces the system of equations
To solve this system, we first observe that Substituting this value into the first two equations gives us the system
Multiplying the second equation by and adding the resulting equation to the first produces
which in turn implies that Substituting this value into the equation yields Thus, solving these equations yields and
It is important to note that the system produced by this method is consistent if and only if we have set up the decomposition correctly. If the system is inconsistent, there is an error in our decomposition.
The method of strategic substitution is based on the assumption that we have set up the decomposition correctly. If the decomposition is set up correctly, then there must be values of and that satisfy [link] for all values of That is, this equation must be true for any value of we care to substitute into it. Therefore, by choosing values of carefully and substituting them into the equation, we may find and easily. For example, if we substitute the equation reduces to Solving for yields Next, by substituting the equation reduces to or equivalently Last, we substitute into the equation and obtain Solving, we have
It is important to keep in mind that if we attempt to use this method with a decomposition that has not been set up correctly, we are still able to find values for the constants, but these constants are meaningless. If we do opt to use the method of strategic substitution, then it is a good idea to check the result by recombining the terms algebraically.
Now that we have the values of and we rewrite the original integral:
Evaluating the integral gives us
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