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[link] shows a random sample of 200 cyclists and the routes they prefer. Let M = males and H = hilly path.

Gender Lake Path Hilly Path Wooded Path Total
Female 45 38 27 110
Male 26 52 12 90
Total 71 90 39 200

  1. Out of the males, what is the probability that the cyclist prefers a hilly path?
  2. Are the events “being male” and “preferring the hilly path” independent events?
  1. P ( H | M ) = 52 90 = 0.5778
  2. For M and H to be independent, show P ( H | M ) = P ( H )
    P ( H | M ) = 0.5778, P ( H ) = 90 200 = 0.45
    P ( H | M ) does not equal P ( H ) so M and H are NOT independent.

Muddy Mouse lives in a cage with three doors. If Muddy goes out the first door, the probability that he gets caught by Alissa the cat is 1 5 and the probability he is not caught is 4 5 . If he goes out the second door, the probability he gets caught by Alissa is 1 4 and the probability he is not caught is 3 4 . The probability that Alissa catches Muddy coming out of the third door is 1 2 and the probability she does not catch Muddy is 1 2 . It is equally likely that Muddy will choose any of the three doors so the probability of choosing each door is 1 3 .

Door choice
Caught or Not Door One Door Two Door Three Total
Caught 1 15 1 12 1 6 ____
Not Caught 4 15 3 12 1 6 ____
Total ____ ____ ____ 1
  • The first entry 1 15 = ( 1 5 ) ( 1 3 ) is P ( Door One Caught )
  • The entry 4 15 = ( 4 5 ) ( 1 3 ) is P ( Door One Not Caught )

Verify the remaining entries.

a. Complete the probability contingency table. Calculate the entries for the totals. Verify that the lower-right corner entry is 1.

a.

Door choice
Caught or Not Door One Door Two Door Three Total
Caught 1 15 1 12 1 6 19 60
Not Caught 4 15 3 12 1 6 41 60
Total 5 15 4 12 2 6 1

b. What is the probability that Alissa does not catch Muddy?

b. 41 60

c. What is the probability that Muddy chooses Door One Door Two given that Muddy is caught by Alissa?

c. 9 19

[link] contains the number of crimes per 100,000 inhabitants from 2008 to 2011 in the U.S.

United states crime index rates per 100,000 inhabitants 2008–2011
Year Robbery Burglary Rape Vehicle Total
2008 145.7 732.1 29.7 314.7
2009 133.1 717.7 29.1 259.2
2010 119.3 701 27.7 239.1
2011 113.7 702.2 26.8 229.6
Total

TOTAL each column and each row. Total data = 4,520.7

  1. Find P ( 2009 Robbery ) .
  2. Find P ( 2010 Burglary ) .
  3. Find P ( 2010 Burglary ) .
  4. Find P (2011 | Rape).
  5. Find P (Vehicle | 2008).

a. 0.0294, b. 0.1551, c. 0.7165, d. 0.2365, e. 0.2575

Try it

[link] relates the weights and heights of a group of individuals participating in an observational study.

Weight/Height Tall Medium Short Totals
Obese 18 28 14
Normal 20 51 28
Underweight 12 25 9
Totals
  1. Find the total for each row and column
  2. Find the probability that a randomly chosen individual from this group is Tall.
  3. Find the probability that a randomly chosen individual from this group is Obese and Tall.
  4. Find the probability that a randomly chosen individual from this group is Tall given that the idividual is Obese.
  5. Find the probability that a randomly chosen individual from this group is Obese given that the individual is Tall.
  6. Find the probability a randomly chosen individual from this group is Tall and Underweight.
  7. Are the events Obese and Tall independent?
Weight/Height Tall Medium Short Totals
Obese 18 28 14 60
Normal 20 51 28 99
Underweight 12 25 9 46
Totals 50 104 51 205
  1. Row Totals: 60, 99, 46. Column totals: 50, 104, 51.
  2. P (Tall) = 50 205 = 0.244
  3. P ( Obese Tall ) = 18 205 = 0.088
  4. P (Tall | Obese) = 18 60 = 0.3
  5. P (Obese | Tall) = 18 50 = 0.36
  6. P ( Tall Underweight ) = 12 205 = 0.0585
  7. No. P (Tall) does not equal P (Tall | Obese).
Practice Key Terms 2

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Source:  OpenStax, Introductory statistics. OpenStax CNX. Aug 09, 2016 Download for free at http://legacy.cnx.org/content/col11776/1.26
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