In other words, the Intermediate Value Theorem tells us that when a polynomial function changes from a negative value to a positive value, the function must cross the
axis.
[link] shows that there is a zero between
and
Using the Intermediate Value Theorem to show there exists a zero.
Intermediate value theorem
Let
be a polynomial function. The
Intermediate Value Theorem states that if
and
have opposite signs, then there exists at least one value
between
and
for which
Using the intermediate value theorem
Show that the function
has at least two real zeros between
and
As a start, evaluate
at the integer values
See
[link] .
1
2
3
4
5
0
–3
2
We see that one zero occurs at
Also, since
is negative and
is positive, by the Intermediate Value Theorem, there must be at least one real zero between 3 and 4.
We have shown that there are at least two real zeros between
and
Show that the function
has at least one real zero between
and
Because
is a polynomial function and since
is negative and
is positive, there is at least one real zero between
and
Writing formulas for polynomial functions
Now that we know how to find zeros of polynomial functions, we can use them to write formulas based on graphs. Because a
polynomial function written in factored form will have an
intercept where each factor is equal to zero, we can form a function that will pass through a set of
intercepts by introducing a corresponding set of factors.
Factored form of polynomials
If a polynomial of lowest degree
has horizontal intercepts at
then the polynomial can be written in the factored form:
where the powers
on each factor can be determined by the behavior of the graph at the corresponding intercept, and the stretch factor
can be determined given a value of the function other than the
x -intercept.
Given a graph of a polynomial function, write a formula for the function.
Identify the
x -intercepts of the graph to find the factors of the polynomial.
Examine the behavior of the graph at the
x -intercepts to determine the multiplicity of each factor.
Find the polynomial of least degree containing all the factors found in the previous step.
Use any other point on the graph (the
y -intercept may be easiest) to determine the stretch factor.
Writing a formula for a polynomial function from the graph
Write a formula for the polynomial function shown in
[link] .
This graph has three
intercepts:
and
The
intercept is located at
At
and
the graph passes through the axis linearly, suggesting the corresponding factors of the polynomial will be linear. At
the graph bounces at the intercept, suggesting the corresponding factor of the polynomial will be second degree (quadratic). Together, this gives us
To determine the stretch factor, we utilize another point on the graph. We will use the
intercept
to solve for
The graphed polynomial appears to represent the function
Three charges q_{1}=+3\mu C, q_{2}=+6\mu C and q_{3}=+8\mu C are located at (2,0)m (0,0)m and (0,3) coordinates respectively. Find the magnitude and direction acted upon q_{2} by the two other charges.Draw the correct graphical illustration of the problem above showing the direction of all forces.
To solve this problem, we need to first find the net force acting on charge q_{2}. The magnitude of the force exerted by q_{1} on q_{2} is given by F=\frac{kq_{1}q_{2}}{r^{2}} where k is the Coulomb constant, q_{1} and q_{2} are the charges of the particles, and r is the distance between them.
Muhammed
What is the direction and net electric force on q_{1}= 5µC located at (0,4)r due to charges q_{2}=7mu located at (0,0)m and q_{3}=3\mu C located at (4,0)m?
Capacitor is a separation of opposite charges using an insulator of very small dimension between them. Capacitor is used for allowing an AC (alternating current) to pass while a DC (direct current) is blocked.
Gautam
A motor travelling at 72km/m on sighting a stop sign applying the breaks such that under constant deaccelerate in the meters of 50 metres what is the magnitude of the accelerate
velocity can be 72 km/h in question. 72 km/h=20 m/s, v^2=2.a.x , 20^2=2.a.50, a=4 m/s^2.
Mehmet
A boat travels due east at a speed of 40meter per seconds across a river flowing due south at 30meter per seconds. what is the resultant speed of the boat
which has a higher temperature, 1cup of boiling water or 1teapot of boiling water which can transfer more heat 1cup of boiling water or 1 teapot of boiling water explain your . answer
I believe temperature being an intensive property does not change for any amount of boiling water whereas heat being an extensive property changes with amount/size of the system.
Someone
Scratch that
Someone
temperature for any amount of water to boil at ntp is 100⁰C (it is a state function and and intensive property) and it depends both will give same amount of heat because the surface available for heat transfer is greater in case of the kettle as well as the heat stored in it but if you talk.....
Someone
about the amount of heat stored in the system then in that case since the mass of water in the kettle is greater so more energy is required to raise the temperature b/c more molecules of water are present in the kettle
pratica A on solution of hydro chloric acid,B is a solution containing 0.5000 mole ofsodium chlorid per dm³,put A in the burret and titrate 20.00 or 25.00cm³ portion of B using melting orange as the indicator. record the deside of your burret tabulate the burret reading and calculate the average volume of acid used?
No. According to Isac Newtons law. this two bodies maybe you and the wall beside you.
Attracting depends on the mass och each body and distance between them.
Dlovan
Are you really asking if two bodies have to be charged to be influenced by Coulombs Law?
Robert
like charges repel while unlike charges atttact
Raymond
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