<< Chapter < Page Chapter >> Page >

Instantiate a new object and call its run method

The code in the main method instantiates a new object of the class named Prob02Runner and calls the run method on that object.

When the run method returns, the main method terminates causing the program to terminate.

Beginning of the class named Prob02Runner

The beginning of the class named Prob02Runner , including the constructor, is shown in Listing 2 .

Listing 2 - Beginning of the class named Prob02Runner.
class Prob02Runner{ public Prob02Runner(){ System.out.println("Display your name here.");}//end constructor

The constructor displays the student's name, producing the first line of output text shown in Figure 5 .

The run method

The run method that is called in Listing 1 is shown in its entirety in Listing 3 .

Listing 3 - The run method.
public void run(){ Picture pix = new Picture("Prob02a.jpg");//Add your name and display the output picture. pix.addMessage("Display your name here.",10,20);//Display the input picture. pix.explore();pix = rotatePicture(pix,35); pix.explore();pix = mirrorUpperQuads(pix); pix = mirrorHoriz(pix);pix.explore(); System.out.println(pix);}//end run

Very familiar code

Except for the calls to the methods named mirrorUpperQuads and mirrorHoriz in Listing 3 , you should already be familiar with all of the code in Listing 3 .

The rotatePicture method

For example, the call to the method named rotatePicture is essentially the same as code that I explained in an earlier module. Therefore, Iwon't explain that method again in this module. You will find the code for the method named rotatePicture in Listing 6 near the end of the module.

Operate on the picture with the rotated image

The original picture is replaced by a picture containing the rotated image shown in Figure 3 . From this point forward, all operations are performed on the Picture object containing the rotated image.

The method named mirrorUpperQuads

The method named mirrorUpperQuads that is called in the run method in Listing 3 is shown in Listing 4 .

Behavior of the method named mirrorUpperQuads

This method mirrors the upper-left quadrant of a picture into the upper-right quadrant as shown in Figure 6 .

Listing 4 - The method named mirrorUpperQuads.
private Picture mirrorUpperQuads(Picture pix){ Pixel leftPixel = null;Pixel rightPixel = null; int midpoint = pix.getWidth()/2;int width = pix.getWidth(); for(int row = 0;row<pix.getHeight()/2;row++){ for(int col = 0;col<midpoint;col++){ leftPixel = pix.getPixel(col,row);rightPixel = pix.getPixel(width-1-col,row);rightPixel.setColor(leftPixel.getColor()); }//end inner loop}//end outer loop return pix;}//end mirrorUpperQuads

Declare four working variables

Listing 4 begins by declaring and initializing four working variables. The purpose of these variables should be obvious on the basisof their names and their initialization expressions.

Copy the pixel colors

Then Listing 4 uses a double nested for loop to copy the colors from the pixels in the upper-left quadrant into thepixels in the upper-right quadrant. This is done in such a way as to form a mirror image about the center point as shown in Figure 6 .

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
Aislinn Reply
cm
tijani
what is titration
John Reply
what is physics
Siyaka Reply
A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
Jude Reply
Can you compute that for me. Ty
Jude
what is the dimension formula of energy?
David Reply
what is viscosity?
David
what is inorganic
emma Reply
what is chemistry
Youesf Reply
what is inorganic
emma
Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
Adjei
please, I'm a physics student and I need help in physics
Adjanou
chemistry could also be understood like the sexual attraction/repulsion of the male and female elements. the reaction varies depending on the energy differences of each given gender. + masculine -female.
Pedro
A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
Krampah Reply
2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
Sahid Reply
you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
Ryan
what's motion
Maurice Reply
what are the types of wave
Maurice
answer
Magreth
progressive wave
Magreth
hello friend how are you
Muhammad Reply
fine, how about you?
Mohammed
hi
Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
yasuo Reply
Who can show me the full solution in this problem?
Reofrir Reply
Got questions? Join the online conversation and get instant answers!
Jobilize.com Reply

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, Object-oriented programming (oop) with java. OpenStax CNX. Jun 29, 2016 Download for free at https://legacy.cnx.org/content/col11441/1.201
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Object-oriented programming (oop) with java' conversation and receive update notifications?

Ask