3.21 To solve problems in context

Mathematics

Measurement and time

Volume

Educator section

Memorandum

1.

1.1 3 cm × 2 cm × 2 cm = 12 cm³

3 cm × 2 cm × 3 cm = 18 cm³

1 cm × 4 cm × 3 cm = 12 cm³

1.2 5 m × 3,5 m × 2 m = 35 m²

1.3 9 cm × 6 cm × 2 cm = 108 cm²

2. 2.1 577 912 cm²

2.1 583 296 cm²

3. (78 cm × 46 cm × 52 cm) ÷ (24 cm × 8 cm × 11 cm)

= 186 576 cm² ÷ 2 112 cm²

= 88,34

= 88 small boxes

Leaner section

Content

Activity: to solve problems in context [lo 1.6.2]

1. Calculate the volume of the following:

1.1

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1.2 A swimming pool 5 m long, 3,5 m wide and 2 m deep.

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1.3 A tin of tuna: 9 cm by 6 cm by 2 cm.

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2. Which container has the biggest volume:

2.1: 106 cm by 94 cm by 58 cm, or

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2.2: 93 cm by 98 cm by 64 cm?.

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3. How many small boxes with the measurements 24 cm × 8 cm × 11 cm can you pack into a big box of 78 cm by 46 cm by 52 cm?

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Assessment

Learning Outcome 1: The learner will be able to recognise, describe and represent numbers and their relationships, and to count, estimate, calculate and check with competence and confidence in solving problems.

Assessment Standard 1.6: We know this when the learner solves problems in context including contexts that may be used to build awareness of other Learning Areas, as well as human rights, social, economic and environmental issues such as:

1.6.2: measurements in Natural Sciences and Technology contexts.