<< Chapter < Page Chapter >> Page >
This module describes what inverse functions are and how they can be used.

Let's go back to Alice, who makes $100/day. We know how to answer questions such as "After 3 days, how much money has she made?" We use the function m ( t ) = 100 t .

But suppose I want to ask the reverse question: “If Alice has made $300, how many hours has she worked?” This is the job of an inverse function. It gives the same relationship, but reverses the dependent and independent variables. t ( m ) = m / 100 . Given any amount of money, divide it by 100 to find how many days she has worked.

  • If a function answers the question: “Alice worked this long, how much money has she made?” then its inverse answers the question: “Alice made this much money, how long did she work?"
  • If a function answers the question: “I have this many spoons, how much do they weigh?” then its inverse answers the question: “My spoons weigh this much, how many do I have?”
  • If a function answers the question: “How many hours of music fit on 12 CDs?” then its inverse answers the question: “How many CDs do you need for 3 hours of music?”

How do you recognize an inverse function?

Let’s look at the two functions above:

m ( t ) = 100 t size 12{m \( t \) ="100"t} {}
t ( m ) = m / 100 size 12{t \( m \) =m/"100"} {}

Mathematically, you can recognize these as inverse functions because they reverse the inputs and the outputs .

3 m ( t ) = 100 t 300 size 12{3 rightarrow m \( t \) ="100"t rightarrow "300"} {}
300 t ( m ) = m / 100 3 size 12{"300" rightarrow t \( m \) =m/"100" rightarrow 3} {}
Inverse functions

Of course, this makes logical sense. The first line above says that “If Alice works 3 hours, she makes $300.” The second line says “If Alice made $300, she worked 3 hours.” It’s the same statement, made in two different ways.

But this “reversal” property gives us a way to test any two functions to see if they are inverses. For instance, consider the two functions:

f ( x ) = 3x + 7 size 12{f \( x \) =3x+7} {}
g ( x ) = 1 3 x 7 size 12{g \( x \) = { { size 8{1} } over { size 8{3} } } x - 7} {}

They look like inverses, don’t they? But let’s test and find out.

2 3x + 7 13 size 12{2 rightarrow 3x+7 rightarrow "13"} {}
13 3 x - 7 13 3 - 7 - 8 3 size 12{"13" rightarrow 1/3x-7 rightarrow "13"/3-7 rightarrow -8/3 } {}
Not inverse functions

The first function turns a 2 into a 13. But the second function does not turn 13 into 2. So these are not inverses.

On the other hand, consider:

f ( x ) = 3x + 7 size 12{f \( x \) =3x+7} {}
g ( x ) = 1 3 x 7 size 12{g \( x \) = { { size 8{1} } over { size 8{3} } } left (x - 7 right )} {}

Let’s run our test of inverses on these two functions.

2 3x + 7 13 size 12{2 rightarrow 3x+7 rightarrow "13"} {}
13 1 3 x 7 2 size 12{"13" rightarrow { { size 8{1} } over { size 8{3} } } left (x - 7 right ) rightarrow 2} {}
Inverse functions

So we can see that these functions do, in fact, reverse each other: they are inverses.

A common example is the Celsius-to-Fahrenheit conversion:

F ( C ) = 9 5 C + 32 size 12{F \( C \) = left ( { {9} over {5} } right )C+"32"} {}
C ( F ) = 5 9 F 32 size 12{C \( F \) = left ( { {5} over {9} } right ) left (F - "32" right )} {}

where C size 12{C} {} is the Celsius temperature and F size 12{F} {} the Fahrenheit. If you plug 100 ° C size 12{"100"°C} {} into the first equation, you find that it is 212 ° F size 12{"212"°F} {} . If you ask the second equation about 212 ° F size 12{"212"°F} {} , it of course converts that back into 100 ° C size 12{"100"°C} {} .

The notation and definition of an inverse function

The notation for the inverse function of f ( x ) size 12{f \( x \) } {} is f 1 ( x ) size 12{f rSup { size 8{ - 1} } \( x \) } {} . This notation can cause considerable confusion, because it looks like an exponent, but it isn’t. f 1 ( x ) size 12{f rSup { size 8{ - 1} } \( x \) } {} simply means “the inverse function of f ( x ) size 12{f \( x \) } {} .” It is defined formally by the fact that if you plug any number x size 12{x} {} into one function, and then plug the result into the other function, you get back where you started. (Take a moment to convince yourself that this is the same definition I gave above more informally.) We can represent this as a composition function by saying that f ( f 1 ( x ) ) = x size 12{f \( f rSup { size 8{ - 1} } \( x \) \) =x} {} .

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
Aislinn Reply
cm
tijani
what is titration
John Reply
what is physics
Siyaka Reply
A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
Jude Reply
Can you compute that for me. Ty
Jude
what is the dimension formula of energy?
David Reply
what is viscosity?
David
what is inorganic
emma Reply
what is chemistry
Youesf Reply
what is inorganic
emma
Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
Adjei
please, I'm a physics student and I need help in physics
Adjanou
chemistry could also be understood like the sexual attraction/repulsion of the male and female elements. the reaction varies depending on the energy differences of each given gender. + masculine -female.
Pedro
A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
Krampah Reply
2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
Sahid Reply
you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
Ryan
what's motion
Maurice Reply
what are the types of wave
Maurice
answer
Magreth
progressive wave
Magreth
hello friend how are you
Muhammad Reply
fine, how about you?
Mohammed
hi
Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
yasuo Reply
Who can show me the full solution in this problem?
Reofrir Reply
Got questions? Join the online conversation and get instant answers!
Jobilize.com Reply

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, Math 1508 (lecture) readings in precalculus. OpenStax CNX. Aug 24, 2011 Download for free at http://cnx.org/content/col11354/1.1
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Math 1508 (lecture) readings in precalculus' conversation and receive update notifications?

Ask