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The variance is a squared measure and does not have the same units as the data. Taking the square root solves the problem. The standard deviation measures the spread in the same units as the data.
Notice that instead of dividing by n=20, the calculation divided by n-1=20-1=19 because the data is a sample. For the sample variance, we divide by the sample size minus one ( ). Why not divide by ? The answer has to do with the population variance. The sample variance is an estimate of the population variance. Based on the theoretical mathematics that lies behind these calculations, dividing by gives a better estimate of the population variance.
The standard deviation, or , is either zero or larger than zero. When the standard deviation is 0, there is no spread; that is, the all the data values are equal to each other. The standard deviation is small when the data are all concentrated close to the mean, and is larger when the data values show more variation from the mean. When the standard deviation is a lot larger than zero, the data values are very spread out about the mean; outliers can make or very large.
The standard deviation, when first presented, can seem unclear. By graphing your data, you can get a better "feel" for the deviations and the standard deviation. You will find that in symmetrical distributions, the standard deviation can be very helpful but in skewed distributions, the standard deviation may not be much help. The reason is that the two sides of a skewed distribution have different spreads. In a skewed distribution, it is better to look at the first quartile, the median, the third quartile, the smallest value, and the largest value. Because numbers can be confusing, always graph your data .
Use the following data (first exam scores) from Susan Dean's spring pre-calculus class:
Data | Frequency | Relative Frequency | Cumulative Relative Frequency |
---|---|---|---|
33 | 1 | 0.032 | 0.032 |
42 | 1 | 0.032 | 0.064 |
49 | 2 | 0.065 | 0.129 |
53 | 1 | 0.032 | 0.161 |
55 | 2 | 0.065 | 0.226 |
61 | 1 | 0.032 | 0.258 |
63 | 1 | 0.032 | 0.29 |
67 | 1 | 0.032 | 0.322 |
68 | 2 | 0.065 | 0.387 |
69 | 2 | 0.065 | 0.452 |
72 | 1 | 0.032 | 0.484 |
73 | 1 | 0.032 | 0.516 |
74 | 1 | 0.032 | 0.548 |
78 | 1 | 0.032 | 0.580 |
80 | 1 | 0.032 | 0.612 |
83 | 1 | 0.032 | 0.644 |
88 | 3 | 0.097 | 0.741 |
90 | 1 | 0.032 | 0.773 |
92 | 1 | 0.032 | 0.805 |
94 | 4 | 0.129 | 0.934 |
96 | 1 | 0.032 | 0.966 |
100 | 1 | 0.032 | 0.998 (Why isn't this value 1?) |
The long left whisker in the box plot is reflected in the left side of the histogram. The spread of the exam scores in the lower 50% is greater (73-33=40) than the spread in the upper 50% (100-73=27). The histogram, box plot, and chart all reflect this. There are a substantial number of A and B grades (80s, 90s, and 100). The histogram clearly shows this. The box plot shows us that the middle 50% of the exam scores (IQR=29) are Ds, Cs, and Bs. The box plot also shows us that the lower 25% of the exam scores are Ds and Fs.
#ofSTDEVs is often called a "z-score"; we can use the symbol z. In symbols, the formulas become:
Sample | = + z s | |
Population | = + z |
Two students, John and Ali, from different high schools, wanted to find out who had the highest grade point average (GPA) when compared to his school. Which student had the highest GPA when compared to his school?
Student | GPA | School Mean GPA | School Standard Deviation |
---|---|---|---|
John | 2.85 | 3.0 | 0.7 |
Ali | 77 | 80 | 10 |
For each student, determine how many standard deviations (#ofSTDEVs) his GPA is away from the average, for his school. Pay careful attention to signs when comparing and interpreting the answer.
;
For John,
For Ali,
John has the better GPA when compared to his school because his GPA is 0.21 standard deviations below his mean while Ali's GPA is 0.3 standard deviations below his mean.
John's z-score of −0.21 is higher than Ali's z-score of −0.3 . For GPA, higher values are better, so we conclude that John has the better GPA when compared to his school.
The following lists give a few facts that provide a little more insight into what the standard deviation tells us about the distribution of the data.
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