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Recall that in Chapter 1, we defined the power of a periodic signal as

p x = 1 T t 0 t 0 + T x 2 ( t ) d t

where T is the period. Using the complex form of the Fourier series, we can write

x ( t ) 2 = n = - c n e j n Ω 0 t m = - c m e j m Ω 0 t *

where we have used the fact that x ( t ) 2 = x ( t ) x ( t ) * , i.e. since x ( t ) is real x ( t ) = x ( t ) * . Applying [link] and [link] gives

x ( t ) 2 = n = - c n e j n Ω 0 t m = - c m * e - j m Ω 0 t = n = - m = - c n c m * e j ( n - m ) Ω 0 t = n = - c n 2 + n m c n c m * e j ( n - m ) Ω 0 t

Substituting this quantity into [link] gives

p x = 1 T t 0 t 0 + T n = - c n 2 + n m c n c m * e j ( n - m ) Ω 0 t d t = n = - c n 2 + 1 T t 0 t 0 + T n m c n c m * e j ( n - m ) Ω 0 t d t

It is straight-forward to show that

1 T t 0 t 0 + T n m c n c m * e j ( n - m ) Ω 0 t d t = 0

This leads to Parseval's Theorem for the Fourier series:

p x = n = - c n 2

which states that the power of a periodic signal is the sum of the magnitude of the complex Fourier series coefficients.

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Source:  OpenStax, Signals, systems, and society. OpenStax CNX. Oct 07, 2012 Download for free at http://cnx.org/content/col10965/1.15
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