<< Chapter < Page Chapter >> Page >
This module covers how zero, negative numbers, and fractions can be used as exponents.

The definition of exponents given at the beginning of this section— 10 6 size 12{"10" rSup { size 8{6} } } {} means 10 10 10 10 10 10 size 12{"10" cdot "10" cdot "10" cdot "10" cdot "10" cdot "10"} {} —does not enable us to answer questions such as:

4 0 = ? size 12{4 rSup { size 8{0} } =?} {}
5 4 = ? size 12{5 rSup { size 8{ - 4} } =?} {}
9 1 2 = ? size 12{9 rSup { size 8{ { { size 6{1} } over { size 6{2} } } } } =?} {}

You can’t “multiply 9 by itself half a time” or “multiply 5 by itself 4 size 12{ - 4} {} times.” In general, the original definition only applies if the exponent is a positive integer .

It’s very important to understand this point. The question is not “What answer does our original definition give in these cases?” The original definition does not give any answer in these cases. If we want to include these numbers, we need a whole new definition of what an exponent is.

In principle, many such definitions are possible. We could define 5 4 size 12{5 rSup { size 8{ - 4} } } {} as 5 / 5 / 5 / 5 size 12{5/5/5/5} {} : in other words, divide four times instead of multiplying four times. Or we could define 5 4 size 12{5 rSup { size 8{ - 4} } } {} as 5 4 size 12{5 rSup { size 8{ - 4} } } {} : take 5 to the fourth power, and then multiply it by 1 size 12{ - 1} {} . Or we could define 5 4 size 12{5 rSup { size 8{ - 4} } } {} as ( 5 ) 4 size 12{ - \( 5 \) rSup { size 8{4} } } {} : take 5 size 12{ - 5} {} to the fourth power (which gives a different answer from the previous definition). It seems at first that we are at liberty to choose any definition we want.

Given that degree of freedom, you may be very surprised at the definitions that are actually used: they seem far more arbitrary and complicated than some others you could come up with.

Definitions: when the exponent is not a positive integer
Zero exponents Negative exponents Fractional exponents (numerator = 1) Fractional exponents (numerator ≠ 1)
Always 1 Go in the denominator Act as roots The numerator is an exponent
The denominator is a root
7 0 = 1
9 0 = 1
x 0 = 1
7 -3 = 1 7 3 = 1 343
x -5 = 1 x 5
1 5 -3 = 5 3
9 1 2 = 9 = 3
2 1 2 = 2
8 1 3 = 8 3 = 2
x 1 4 = x 4
8 2 3 = 8 2 3 or ( 8 3 ) 2
Order doesn't matter!
8 2 3 = 64 3 = 4 or ( 8 3 ) 2 = 2 2 = 4
8 3 2 = 8 3 or ( 8 ) 3

Note that you can combine these definitions. For instance, 8 2 3 size 12{8 rSup { size 8{ - { { size 6{2} } over { size 6{3} } } } } } {} is a negative, fractional exponent. The negative exponent means, as always, “put me in the denominator.” So we can write:

8 2 3 = 1 8 2 3 = 1 8 2 3 = 1 4 size 12{8 rSup { size 8{ - { { size 6{2} } over { size 6{3} } } } } = { {1} over {8 rSup { { { size 6{2} } over { size 6{3} } } } } } size 12{ {}= { {1} over { nroot {3} {8 rSup {2} } } } } size 12{ {}= { {1} over {4} } }} {}

Ok, so why define exponents that way?

These are obviously not chosen to be the simplest possible definitions. But they are chosen to be consistent with the behavior of positive-integer exponents.

One way to see that consistency is to consider the following progression:

19 4 = 19 19 19 19 size 12{"19" rSup { size 8{4} } ="19" cdot "19" cdot "19" cdot "19"} {}
19 3 = 19 19 19 size 12{"19" rSup { size 8{3} } ="19" cdot "19" cdot "19"} {}
19 2 = 19 19 size 12{"19" rSup { size 8{2} } ="19" cdot "19"} {}
19 1 = 19 size 12{"19" rSup { size 8{1} } ="19"} {}

What happens each time we decrease the exponent by 1? Your first response might be “we have one less 19.” But what is really happening, mathematically, to the numbers on the right? The answer is that, with each step, they are dividing by 19. If you take 19 19 19 19 size 12{"19" cdot "19" cdot "19" cdot "19"} {} , and divide it by 19, you get 19 19 19 size 12{"19" cdot "19" cdot "19"} {} . Divide that by 19 again, and you get 19 19 size 12{"19" cdot "19"} {} ...and so on. From this we can formulate the following principle for the powers of 19:

Whenever you subtract 1 from the exponent, you divide the answer by 19.

As I said earlier, we want the behavior of our new exponents to be consistent with the behavior of the old (positive-integer) exponents. So we can continue this progression as follows:

19 0 = 19 19 = 1 size 12{"19" rSup { size 8{0} } = { {"19"} over {"19"} } =1} {}
19 1 = 1 19 size 12{"19" rSup { size 8{ - 1} } = { {1} over {"19"} } } {}
19 2 = 1 19 19 = 1 19 2 size 12{"19" rSup { size 8{ - 2} } = { { { { size 8{1} } over { size 8{"19"} } } } over {"19"} } = { {1} over {"19" rSup { size 8{2} } } } } {}

...and so on. We can arrive at our definitions anything 0 = 1 size 12{"anything" rSup { size 8{0} } =1} {} and negative exponents go in the denominator by simply requiring this progression to be consistent.

More rigorously, we can find all our exponent definitions by using the laws of exponents . For instance, what is 4 0 size 12{4 rSup { size 8{0} } } {} ? We can approach this question indirectly by asking: what is 4 2 4 2 size 12{ { {4 rSup { size 8{2} } } over {4 rSup { size 8{2} } } } } {} ?

  • The second law of exponents tells us that 4 2 4 2 = 4 2 2 size 12{ { {4 rSup { size 8{2} } } over {4 rSup { size 8{2} } } } =4 rSup { size 8{2 - 2} } } {} , which is of course 4 0 size 12{4 rSup { size 8{0} } } {} .
  • But of course, 4 2 4 2 size 12{ { {4 rSup { size 8{2} } } over {4 rSup { size 8{2} } } } } {} is just 16 16 size 12{ { {"16"} over {"16"} } } {} , or 1.
  • Since 4 2 4 2 size 12{ { {4 rSup { size 8{2} } } over {4 rSup { size 8{2} } } } } {} is both 4 0 size 12{4 rSup { size 8{0} } } {} and 1, 4 0 size 12{4 rSup { size 8{0} } } {} and 1 must be the same thing!

The proofs given below all follow this pattern. They use the laws of exponents to rewrite expressions such as 4 2 4 2 size 12{ { {4 rSup { size 8{2} } } over {4 rSup { size 8{2} } } } } {} , and go on to show how zero, negative, and fractional exponents must be defined. We started with the definition of an exponent for a positive integer, 10 6 = 10 10 10 10 10 10 size 12{"10" rSup { size 8{6} } ="10" cdot "10" cdot "10" cdot "10" cdot "10" cdot "10"} {} . From there, we developed the laws of exponents. Now we find that, if we want those same laws to apply to other kinds of exponents, there is only one correct way to define those other kinds of exponents.

Proofs: when the exponent is not a positive integer
Zero exponents Negative exponents Fractional exponents (numerator = 1) Fractional exponents (numerator ≠ 1)
Always 1 Go in the denominator Act as roots The numerator is an exponent
The denominator is a root
4 2 4 2 = 4 2 - 2 = 4 0
but 4 2 4 2 = 16 16 = 1
so 4 0 must be 1!
10 1 10 3 = 10 1 - 3 = 10 -2
but 10 1 10 3 = 10 10 · 10 · 10 = 1 10 · 10
so 10 -2 must be 1 10 2
( 9 1 2 ) 2 = 9 1 2 · 2 = 9 1 = 9
So what is 9 1 2 ?
Well, when you square it, you get 9.
So it must be 9 , or 3!
8 2 3 = ( 8 1 3 ) 2 = ( 8 3 ) 2
or
8 2 3 = ( 8 2 ) 1 3 = 8 2 3

You may want to experiment with making these proofs more general and more rigorous by using letters instead of numbers. For instance, in the third case, we could write:

( x 1 a ) a = x 1 a ( a ) = x 1 size 12{ \( x rSup { size 8{ { { size 6{1} } over { size 6{a} } } } } \) rSup {a} size 12{ {}=x rSup { left ( { { size 6{1} } over { size 6{a} } } right ) \( a \) } } size 12{ {}=x rSup {1} }} {}
( x 1 a ) a = x size 12{ \( x rSup { size 8{ { { size 6{1} } over { size 6{a} } } } } \) rSup {a} size 12{ {}=x}} {}
x a a = x a size 12{ nroot { size 8{a} } { left (x rSup { size 8{ {1} wideslash {a} } } right ) rSup { size 8{a} } } = nroot { size 8{a} } {x} } {}
x 1 a = x a size 12{x rSup { size 8{ { { size 6{1} } over { size 6{a} } } } } = nroot {a} {x} } {}

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
Aislinn Reply
cm
tijani
what is titration
John Reply
what is physics
Siyaka Reply
A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
Jude Reply
Can you compute that for me. Ty
Jude
what is the dimension formula of energy?
David Reply
what is viscosity?
David
what is inorganic
emma Reply
what is chemistry
Youesf Reply
what is inorganic
emma
Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
Adjei
please, I'm a physics student and I need help in physics
Adjanou
chemistry could also be understood like the sexual attraction/repulsion of the male and female elements. the reaction varies depending on the energy differences of each given gender. + masculine -female.
Pedro
A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
Krampah Reply
2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
Sahid Reply
you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
Ryan
what's motion
Maurice Reply
what are the types of wave
Maurice
answer
Magreth
progressive wave
Magreth
hello friend how are you
Muhammad Reply
fine, how about you?
Mohammed
hi
Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
yasuo Reply
Who can show me the full solution in this problem?
Reofrir Reply
Got questions? Join the online conversation and get instant answers!
Jobilize.com Reply

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, Math 1508 (lecture) readings in precalculus. OpenStax CNX. Aug 24, 2011 Download for free at http://cnx.org/content/col11354/1.1
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Math 1508 (lecture) readings in precalculus' conversation and receive update notifications?

Ask