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2.13 Fractions - 09

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Mathematics

Common fractions

Educator section

Memorandum

24.1 ( )

or

x

+

_

  • (i) = 7 2 size 12{ { { size 8{7} } over { size 8{2} } } } {} x 30 7 size 12{ { { size 8{"30"} } over { size 8{7} } } } {} - 10

= 210 14 size 12{ { { size 8{"210"} } over { size 8{"14"} } } } {} - 10

= 15 – 10

s = 5

  1. = 32 - 11 3 4 size 12{ { { size 8{3} } over { size 8{4} } } } {}

v = 20 1 4 size 12{ { { size 8{1} } over { size 8{4} } } } {}

  1. = 23 4 size 12{ { { size 8{"23"} } over { size 8{4} } } } {} x 4 7 size 12{ { { size 8{4} } over { size 8{7} } } } {}

= 23 7 size 12{ { { size 8{"23"} } over { size 8{7} } } } {}

p = 3 2 7 size 12{ { { size 8{2} } over { size 8{7} } } } {}

26. a) Method: Cancel out

Answer: 1 8 size 12{ { { size 8{1} } over { size 8{8} } } } {}

b) 1 25 size 12{ { { size 8{1} } over { size 8{"25"} } } } {}

Leaner section

Content

Activity: mixed calculations [lo 1.10]

24. MIXED CALCULATIONS

24.1 Do you still remember?

  • Write down the order of operations below:

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24.2 Now apply this to the following:

(i) s = 3 1 2 × 4 2 7 − 2 3 of 15 size 12{s=3 { { size 8{1} } over { size 8{2} } } times 4 { { size 8{2} } over { size 8{7} } } - { { size 8{2} } over { size 8{3} } } `"of"`"15"} {}

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(ii) v = 1 2 of 64 − 7 1 2 + 4 1 4 size 12{v= { { size 8{1} } over { size 8{2} } } `"of"`"64" - left (7 { { size 8{1} } over { size 8{2} } } +4 { { size 8{1} } over { size 8{4} } } right )} {}

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(iii) p = 5 3 4 ÷ 3 1 8 − 1 3 4 size 12{p=5 { { size 8{3} } over { size 8{4} } } div left (3 { { size 8{1} } over { size 8{8} } } - 1 { { size 8{3} } over { size 8{4} } } right )} {}

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25. Time for self-assessment

26. BRAIN-TEASERS!

a) What is the answer of the following? Try and solve it without long calculations!

o = 1 − 1 2 × 1 − 1 3 × 1 − 1 4 × 1 − 1 5 × 1 − 1 6 × 1 − 1 7 × 1 − 1 8 size 12{o= left (1 - { { size 8{1} } over { size 8{2} } } right ) times left (1 - { { size 8{1} } over { size 8{3} } } right ) times left (1 - { { size 8{1} } over { size 8{4} } } right ) times left (1 - { { size 8{1} } over { size 8{5} } } right ) times left (1 - { { size 8{1} } over { size 8{6} } } right ) times left (1 - { { size 8{1} } over { size 8{7} } } right ) times left (1 - { { size 8{1} } over { size 8{8} } } right )} {}

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b) If you continue with the pattern to. . . 1 − 1 25 size 12{ times left (1 - { { size 8{1} } over { size 8{"25"} } } right )} {} , what will the answer be then?

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Assessment

Learning Outcome 1: The learner will be able to recognise, describe and represent numbers and their relationships, and to count, estimate, calculate and check with competence and confidence in solving problems.

Assessment Standard 1.10: We know this when the learner uses a range of strategies to check solutions and judges the reasonableness of solutions.

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Source:  OpenStax, Mathematics grade 7. OpenStax CNX. Sep 16, 2009 Download for free at http://cnx.org/content/col11075/1.1
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